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Eduardwww [97]
3 years ago
8

Please check if I got it right or correct it

Biology
1 answer:
natka813 [3]3 years ago
5 0
It's hard to understand like only a part of the page. Could you take a picture of the whole page. Thanks.
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In Griffith's experiments with Streptococcus pneumoniae, rough nonencapsulated streptococci were converted into smooth encapsula
larisa86 [58]

Answer:

The correct answer is - transformation.

Explanation:

Griffith's experiment was performed by Fredrick Griffith with Streptococcus pneumoniae. Streptococcus P. are rough non encapsulated streptococci that are converted into smooth encapsulated streptococci bacteria in presence of heat-killed smooth encapsulated bacteria.

This experiment was the first experiment that showed that this bacteria can get DNA by the process of transformation.

He suggested that the nonencapsulated bacteria had been transformed into the encapsulated smooth bacteria strain by the transformation process that was somehow part of the dead encapsulated strain bacteria.

Thus, the correct answer - transformation.

3 0
3 years ago
Which of the following accurately describes nutrient limitation?
Cloud [144]

Answer is c. If one essential nutrient within an ecosystem runs out, primary productivity will be limited

According to Vitousek et al., 2010, nutrient limitation defined as meaningful additions of an essential element in biologically available forms which increases the rate of primary productivity or increase in the biomass in an ecosystem. Alternately, nutrient limitation may also explained as when the supply of one essential nutrient of the ecosystem runs out the primary productivity of the plants will be limited.

5 0
3 years ago
A 10-7 is performed on a culture of bacteria in order to perform viable plate counts. From the dilution, *0.1 mL* of solution is
marishachu [46]

Answer:

66 * 10^8 CFU/mL

Explanation:

Given -

a) Number of colonies of bacteria is equal to 66

b) Total volume of the solution is equal to 0.1 mL

c) Dilution factor is equal to 10^{-7}

As we know that

CFU/mL = \frac{N * DF}{V}

Where N is the number of bacterial colonies, DF is the dilution factor and V is the volume

Substituting the given values in above equation, we get -

CFU/mL = \frac{66* 10^7}{0.1} \\= 66*10^8

5 0
3 years ago
Which example best shows conversation of resources
mariarad [96]
I think is c i hope i am right if not that k k

Just let me know k
4 0
3 years ago
Read 2 more answers
What is the scientific name given to the movement of air into and out of the lungs?
Veronika [31]

Answer:

Pulmonary ventilation

7 0
2 years ago
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