Answer:
it gives CH2OH-CH2OH(ethylene glycol +MnO2
Explanation:
Answer:
81.04°C
Explanation:
Heat loss by water = Heat gained by Aluminum
Heat loss by water;
H = MCΔT
ΔT = 100 - T2
M = 580g
c = 4.2
H = 580 * 4.2 (100 - T2)
H = 243600 - 2436T2
Heat ganed by Aluminium
H = MCΔT
ΔT = T2 - 24
M = 900g
c = 0.9
H = 900 * 0.9 (T2 - 24)
H = 810 T2 - 19440
243600 - 2436T2 = 810 T2 - 19440
243600 + 19440 = 810 T2 + 2436T2
263040 = 3246 T2
T2 = 81.04°C
Assumption;
Assume that energy diffuses throughout the pan and water so that all parts reach the same final temperature.
Answer:
Explanation:
a) O (oxygen) but there's not enough info to determine the isotope
b) superscript-37 subscript-17 Cl
c) superscript-60 subscript-27 Co
d) superscript-57 subscript-26 Fe
e) don't know what you mean here
f) superscript-7 subscript-3 Li
Edit:
a) superscript-17 subscript-8 O
e) superscript-131 subscript-53 I