The balanced equation for the above reaction is
HBr + KOH ---> KBr + H₂O
stoichiometry of HBr to KOH is 1:1
HBr is a strong acid and KOH is a strong base and they both completely dissociate.
The number of HBr moles present - 0.25 M / 1000 mL/L x 52.0 mL = 0.013 mol
The number of KOH moles added - 0.50 M / 1000 mL/L x 26.0 mL = 0.013 mol
the number of H⁺ ions = number of OH⁻ ions
therefore complete neutralisation occurs.
Therefore solution is neutral. At 25 °C, when the solution is neutral, pH = 7.
Then pH of solution is 7
Answer is: <span>the predicted </span>density for calcium is 1.61 g/cm³.
d(Sr) = 2.63 g/cm³; density for strontium.
d(Ba) = 3.65 g/cm³; density for barium.
Ar(Sr) = 87.62 atomic weight for strontium.
Ar(Ba) = 137.33; atomic weight for barium.
Ar(Ca) = 40.08; atomic weight for calcium.
d(Ba) - d(Sr) = 3.65 g/cm³ - 2.63 g/cm³.
d(Ba) - d(Sr) = 1.02 g/cm³.
d(Ca) = d(Sr) - 1.02 g/cm³.
d(Ca) = 2.63 g/cm³ - 1.02 g/cm³.
d(Ca) = 1.61 g/cm³.
Explanation:
K3P = Potassium phosphide
The heated air temperature from inside the balloon more likely rises since it can't escape its trapped resulting in different density from the cooler air, the cooler air from the outside is a bit denser than the heated.
