What does the density of ocean water depend upon

Chemistry

2 answers:

dolphi86 [110]3 years ago

7 0

It depends on the temperature and salinity if the water.

OverLord2011 [107]3 years ago

3 0

It depends on depth

Hope this helps :)

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Explain how you know that no new element with an atomic number less than 100 will be discovered

Klio2033 [76]

The elements are identified by its aomic number and they are placed in the periodic table in ascending order of atomic number.

There is one unique element for a given atomic number.

For example, atomic number 1 identifies Hydrogen and there cannot be another different element with the same atomic number.

All the elements with atomic numbers from 1 to 118 have been discovered. So, you know that there is not room for new products with atomic number equal or less than 118.

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3 years ago

What was the original pressure in a rigid container if the new pressure is 82.5atm and the temperature was raised from 44C to 67

zhenek [66]

Answer: 54 atm

Explanation:

I did 67/82.5 then got 0.8121212121. I them divided 44 by 0.81212121 and got 54.1791044776

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3 years ago

What is an orbital?

Alika [10]

Is a mathematical function describing the location and wave

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3 years ago

Write a chemical equation for the acid-base reaction that occurs when p-phenetidine is dissolved in hcl. why is

melisa1 [442]

<h3><u>Answer;</u></h3>

EtO-PHE-NH2 + H+ _______ EtO-PHE-NH3+ Cl-

<h3><u>Explanation;</u></h3>

<em><u>p-phenetidine is p-ethoxy aniline so the amino group acts as a base. The free electron pair on nitrogen will form a coordinate covalent bond with the H+ from the ionized HCl. </u></em>
HCl is used for the acid-base reaction in p-phenetidine in amide synthesis of acetophenetidin rather than water becuase HCl's polarity contributes to a reaction driven to the right. It protonates the amine group, making it easy to dissolve.

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3 years ago

RATE LAW QUESTION !

vivado [14]

In general, we have this rate law express.:

$\mathrm{Rate} = k \cdot [A]^x [B]^y$
we need to find x and y

ignore the given overall chemical reaction equation as we only preduct rate law from mechanism (not given to us).

then we go to compare two experiments in which only one concentration is changed

compare experiments 1 and 4 to find the effect of changing [B]
divide the larger [B] (experiment 4) by the smaller [B] (experiment 1) and call it Δ[B]

Δ[B]= 0.3 / 0.1 = 3

now divide experiment 4 by experient 1 for the given reaction rates, calling it ΔRate:

ΔRate = 1.7 × 10⁻⁵ / 5.5 × 10⁻⁶ = 34/11 = 3.090909...

solve for y in the equation $\Delta \mathrm{Rate} = \Delta [B]^y$

$3.09 = (3)^y \implies y \approx 1$

To this point, $\mathrm{Rate} = k \cdot [A]^x [B]^1$

do the same to find x.
choose two experiments in which only the concentration of B is unchanged:

Dividing experiment 3 by experiment 2:
Δ[A] = 0.4 / 0.2 = 2
ΔRate = 8.8 × 10⁻⁵ / 2.2 × 10⁻⁵ = 4

solve for x for $\Delta \mathrm{Rate} = \Delta [A]^x$

$4= (2)^x \implies x = 2$

the rate law is

Rate = k·[A]²[B]

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3 years ago