Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
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We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
A branch of mathematics that uses variables is algebra
Any perpendicular line has a negative reciprocal slope. So your slope would be 2. The. You would have the equation : y=2x+b. You would then replace the coordinate (5,6) with x and y on your line to solve for b. Your equation would be : y=2x-4
Answer:
29.4 cm
Step-by-step explanation:
The length of the space diagonal can be found to be the root of the squares of the three orthogonal edge lengths. For a cube, those edge lengths are all the same, so the diagonal length is ...
d = √(17^2 + 17^2 +17^2) = 17√3 ≈ 29.4 . . . . cm
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Consider a rectangular prism with edge lengths a, b, c. Then the face diagonal of the face perpendicular to edge "a" has length ...
(face diagonal)^2 = (b^2 +c^2)
and the space diagonal has length ...
(space diagonal)^2 = a^2 + (face diagonal)^2 = a^2 +b^2 +c^2
So, the length of the space diagonal is ...
space diagonal = √(a^2 +b^2 +c^2)
when the prism is a cube, these are all the same (a=b=c). This is the formula we used above.
