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vladimir1956 [14]
2 years ago
15

Classify the triangle based on the side lengths 9, 40 and 41.

Mathematics
1 answer:
artcher [175]2 years ago
8 0

Answer: right triangle

Step-by-step explanation: 9, 40, and 41 are examples of Pythagorean triples.

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12. Find the surface area of each figure to the nearest tenth.
Zolol [24]

Answer:

  12a. 471.2 cm²

  12b. 60 m²

Step-by-step explanation:

Part A.

The surface area of each figure is the sum of the end area and the lateral area.

  <u>cylinder</u>

  S = (2)(πr²) +2πrh = 2πr(r +h)

  S = 2π(5 cm)(5 cm +10 cm) =150π cm² ≈ 471.2 cm²

__

  <u>triangular prism</u>

  S = (2)(1/2)bh + PL . . . . b=triangle base; h=triangle height; P=triangle perimeter; L=length of prism

  S = (4 m)(1.5 m) + ((4 + 2·2.5) m)(6 m) = (6 + 54) m² = 60 m²

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Part B.

Surface area is useful in the real world wherever products are made from sheets of material or wherever coverings are applied.

Carpeting or other flooring, paint, wallpaper are all priced in terms of the area they cover, for example.

The amount of material used to make containers in the shapes shown will depend on the area of these containers (and any material required for seams).

6 0
2 years ago
Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth.
likoan [24]

Answer:

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

Step-by-step explanation:

Consider, the given Quadratic equation, x^2+4=6x

This can be written as ,  x^2-6x+4=0

We have to solve using quadratic formula,

For a given quadratic equation ax^2+bx+c=0 we can find roots using,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}  ...........(1)

Where,  \sqrt{b^2-4ac} is the discriminant.

Here, a = 1 , b = -6 , c = 4

Substitute in (1) , we get,

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

\Rightarrow x=\frac{-(-6)\pm\sqrt{(-6)^2-4\cdot 1 \cdot (4)}}{2 \cdot 1}

\Rightarrow x=\frac{6\pm\sqrt{20}}{2}

\Rightarrow x=\frac{6\pm 2\sqrt{5}}{2}

\Rightarrow x={3\pm \sqrt{5}}

\Rightarrow x_1={3+\sqrt{5}} and \Rightarrow x_2={3-\sqrt{5}}

We know \sqrt{5}=2.23607(approx)

Substitute, we get,

\Rightarrow x_1={3+2.23607}(approx) and \Rightarrow x_2={3-2.23607}(approx)

\Rightarrow x_1={5.23607}(approx) and \Rightarrow x_2=0.76393}(approx)

Thus, the two root of the given quadratic equation x^2+4=6x is 5.24 and 0.76 .

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2 years ago
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What is the slope and y intercept of y=3x+4
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The slope is 3 and y-intercept is 4
y=mx+b
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2 years ago
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Helppp me for Brainlyiest pls provide proofff or nun
alexandr402 [8]

Answer:

2a + b/4

Step-by-step explanation:

The expression is the sum of two terms (2a + b/4)

The first term is the <u>product (</u>Multiply<u>)</u> of 2 and a (2a)

The second term is the <u>quotient</u> (Divide) of b and 4 (b/4)

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Terms: Binomial
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