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lesya692 [45]
3 years ago
7

0.4 to the 6th power

Mathematics
2 answers:
kaheart [24]3 years ago
6 0
.4^6 = .004096 Hoped this helps.
just olya [345]3 years ago
6 0
4^6 = .004096
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The initial temperature of a cup of tea is 200ºF. The surrounding temperature is 70ºF, and the value of the constant k is 0.6.
Nezavi [6.7K]

Newton's Law of Cooling states that the change of the temperature of an object is proportional to the difference between its own temperature and the ambient temperature over time.

Therefore when expressed mathematically, this is equivalent to:

dT = - k (T – Ts) dt

dT / (T – Ts) = - k dt

Integrating:

ln [(T2– Ts) / (T1– Ts)] = - k (t2 – t1)

Before we plug in the values, let us first convert the temperatures into absolute values R (rankine) by adding 460.

R = ˚F + 460

T1 = 200 + 460 = 660 R

Ts = 70 + 460 = 530 R

ln [(T2– 530) / (660 – 530)] = - 0.6 (2 - 0)

T2 = 569.16 R

T2 = 109 ºF

Answer: After 2 hours, it will be 109 ºF

6 0
3 years ago
Prove that if a and b are integers, then a^2-4b egal or non-egal 2
Lera25 [3.4K]

Answer:

tex]a^2 - 4b \neq 2[/tex]

Step-by-step explanation:

We are given that a and b are integers, then we need to show that a^2 - 4b \neq 2

Let  a^2 - 4b = 2

If a is an even integer, then it can be written as a = 2c, then,

a^2 - 4b = 2\\(2c)^2 - 4b =2\\4(c^2 -b) = 2\\(c^2 -b) =\frac{1}{2}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

If a is an odd integer, then it can be written as a = 2c+1, then,

a^2 - 4b = 2\\(2c+1)^2 - 4b =2\\4(c^2+c-b) = 2\\(c^2+c-b) =\frac{1}{4}

RHS is a fraction but LHS can never be a fraction, thus it is impossible.

Thus, our assumption was wrong and a^2 - 4b \neq 2.

7 0
3 years ago
Helpp me in geometry please
LekaFEV [45]
Hi there !

You have a formule. You just have to apply it.

Let's do it then !

First of all, you must write the coordinates of the point E and F.

Therefore :

E(-2;-4)
F(2;2)

So here, we have :

x_{1} =-2
y_{1} =-4

x_{2} =2
y_{2} =2

Now, Let's apply the formula :

M((-2+2)/2 ; (-4+2)/2)
M(0;-1)

In short, the answer would be : B) (0;-1).

Hope this helps !

Photon

4 0
3 years ago
The lin 2x - 3y = 4 does not passes through the point :
Ymorist [56]

Answer:

The choose D (2, –1)

2x-3y=4 —> 3y=2X-4 —> y= 2/3x – 4/3

y=mx+b —> So ; m= 2/3 , b= - 4/3

y-intercept :(0, -4/3)

0=2/3x –4/3 —> 2/3x = 4/3 —> X=2

x-intercept ; (2,0)

By drawing a straight line from point 2 on the x-axis and point -4/3 on the y-axis, the points that are on the axis have been extracted, but the point (2,-1) is not on the axis . :)

I hope it helped you ^_^

3 0
2 years ago
8÷2(2+2)= what is the solution​
riadik2000 [5.3K]
Add the things in the bracket first so
2+2 = 4
then you do the 8 ÷ 2 = 4

then you multiply them together. this is because the number next to the bracket has a hidden multiply sign so

4 x 4 = 16

answer is 16
7 0
3 years ago
Read 2 more answers
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