1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesya692 [45]
2 years ago
7

0.4 to the 6th power

Mathematics
2 answers:
kaheart [24]2 years ago
6 0
.4^6 = .004096 Hoped this helps.
just olya [345]2 years ago
6 0
4^6 = .004096
You might be interested in
Please help ASAP! <br> X= <br><br> A) 4<br> B) 7<br> C) 9
melisa1 [442]

Answer:

C) x = 9

Step-by-step explanation:

When two segments intersect in a circle like so, the product of the two parts of one segment will be equal to the product of the two parts of the other segment.

So,<em> 3 * 6 = x * 2</em>

Multiply: 18 = x * 2

Divide: x = 9

8 0
3 years ago
Read 2 more answers
A particular computer takes 12 minutes to download a 36 minute TV show. how long will it take the computer to download a 1.5 hr
sladkih [1.3K]
Let x = movie download time
\frac{12}{36}  =  \frac{x}{90}
36x = 1080
x = 30
30 minutes
5 0
2 years ago
Which is greater 4/5 or 60%<br><br> i need help
Kisachek [45]

Answer:

4/5 is greater

Step-by-step explanation:

60% = 60/100

4/5 = 80/100

80>60

5 0
3 years ago
Read 2 more answers
An accounting firm is planning for the next tax preparation season. From last years returns, the firm collects a systematic rand
Elena L [17]

Answer:

a)From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

b) We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Part a

From the central limit theorem we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard error for the mean would be:

\sigma_{\bar X}= \frac{140}{\sqrt{100}} =14

Part b

We want this probability:

P(\bar X >120)

And we can use the z score formula given by:

z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z = \frac{120-90}{\frac{140}{\sqrt{100}}}= 2.143

And we can find this probability with the complement rule and the normal standard deviation or excel and we got:

P( z>2.143) = 1-P(Z

4 0
3 years ago
Please Identify the congruent triangles in the figure.
Tpy6a [65]

The missing steps are each right angles and \angle R \cong \angle O.

Solution:

Step 1: Given data:

\overline {P Q} \cong \overline{M N}

\overline{Q R} \cong \overline{N O}

\overline{P R} \cong \overline{M O}

Step 2: In the two polygons,

\angle Q =90^\circ and \angle N =90^\circ

\angle Q \cong \angle N (Each right angle)

Step 3: Given

\angle P \cong \angle M

Step 4: By third angle theorem,

If two angles in one triangle are congruent to the two angles in the other triangle, then the third angles in the triangles also congruent.

\angle R \cong \angle O

Step 5: By the definition of congruent polygons,

If two same shape polygons have all the angles are congruent and all the corresponding sides are congruent then the polygons are congruent.

Hence \Delta P Q R \cong \Delta M N O.

Therefore the missing steps are each right angles and \angle R \cong \angle O.

5 0
3 years ago
Other questions:
  • Find the equation for the linear function that passes through the points (−5,−6) and (10,3). Answers must use whole numbers and/
    6·2 answers
  • What is the length of little a
    6·1 answer
  • Assume that a procedure yields a geometric distribution where the probability of success is 63%. Use the geometric probability f
    14·1 answer
  • During a vacation together bob spent twice as much as Josh who spent four times as much as Ralph. If Bob and Ralph together spen
    9·2 answers
  • Let f be a function. Use each statement to find the coordinates of a point on the graph of f. f (5) = 9
    6·2 answers
  • What is the sum of 5(−3.4k−7) (3k 21) =
    5·1 answer
  • Plz help me omg it’s ixl and I don’t get it at all
    5·1 answer
  • The distance from the center of a center of a compact disc to the edge of the disc is 6 centimeters. What is the area of the com
    15·1 answer
  • 5.732-4.98 i need help im in 6th grade and i don't know if its 52.34 or 0.752
    9·2 answers
  • Which equation or inequality represents the following description?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!