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frez [133]
3 years ago
8

Consider a transformer used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 4 turns in it

s secondary coil, and an input voltage of 120 V. What is the voltage output in volts, of the transformer used for to charge the batteries?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

Output Voltage = 0.96 volts

Explanation:

As we know by the equation of transformer we have

\frac{V_1}{V_2} = \frac{N_1}{N_2}

here we know that

V_1 = voltage of primary coil = 120 Volts

V_2 = voltage of secondary coil

N_1 = number of turns in primary coil = 500

N_2 = number of turns in secondary coil = 4

now we will have

\frac{120}{V} = \frac{500}{4}

V = 0.96 Volts

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Answer:

Part a)

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Explanation:

Part a)

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Part b)

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At the instant the traffic light turns green, an automobile starts with a constant acceleration a of 2.5 m/s2. At the same insta
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Answer:

6.96 s

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<u>Assume:</u>

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At the moment the automobile and the truck both meat each other the distance travel by both vehicles must be the same.

\therefore \textrm{Distance traveled by the automobile }=\textrm{Distance traveled by the truck}\\\Rightarrow ut+\dfrac{1}{2}at^2=vt\\\Rightarrow (0)t+\dfrac{1}{2}\times 2.5\times t^2=8.7t\\\Rightarrow 1.25t^2=8.7t\\\Rightarrow 1.25t^2-8.7t=0\\\Rightarrow t(1.25t-8.7)=0\\\Rightarrow t = 0\,\,\,or\,\,\, t = \dfrac{8.7}{1.25}\\\Rightarrow t = 0\,\,\,or\,\,\, t = 6.96\\

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