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frez [133]
3 years ago
8

Consider a transformer used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 4 turns in it

s secondary coil, and an input voltage of 120 V. What is the voltage output in volts, of the transformer used for to charge the batteries?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

Output Voltage = 0.96 volts

Explanation:

As we know by the equation of transformer we have

\frac{V_1}{V_2} = \frac{N_1}{N_2}

here we know that

V_1 = voltage of primary coil = 120 Volts

V_2 = voltage of secondary coil

N_1 = number of turns in primary coil = 500

N_2 = number of turns in secondary coil = 4

now we will have

\frac{120}{V} = \frac{500}{4}

V = 0.96 Volts

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<h3>Further explanation</h3>

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N = 195 turns

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500 * 10^{-6} = \frac{4\pi *10^{-7}  N^{2} *4\pi  *10^{-4}  }{0.12}\\500 * 10^{-6} = 0.00000001316N^{2} \\N^{2} = \frac{500 * 10^{-6}}{0.00000001316}\\N^{2} = 37995.44\\N = \sqrt{37995.44} \\N = 194.92 turns

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