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frez [133]
3 years ago
8

Consider a transformer used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 4 turns in it

s secondary coil, and an input voltage of 120 V. What is the voltage output in volts, of the transformer used for to charge the batteries?
Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

Output Voltage = 0.96 volts

Explanation:

As we know by the equation of transformer we have

\frac{V_1}{V_2} = \frac{N_1}{N_2}

here we know that

V_1 = voltage of primary coil = 120 Volts

V_2 = voltage of secondary coil

N_1 = number of turns in primary coil = 500

N_2 = number of turns in secondary coil = 4

now we will have

\frac{120}{V} = \frac{500}{4}

V = 0.96 Volts

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Complete Question

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Answer:

The  value  is  J_n  =  -0.864 \  A/cm^2

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   d p_{n_o} =  10^8 * (2.25 *10^{4} ) - 2.25 *10^{4}

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substitute

    1.60 *10^{-19} \  C for  q  and  w_2 =50 nm =  50*10^{-9} m  =  5*10^{-6} cm

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    J_n  =  -1.60 *10^{-19} *12 *  \frac{2.25 *10^{12} }{ 5*10^{-6} - 0 }

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