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3 years ago

How could the position data from a motion sensor be used to create a velocity--time graph?

1 answer:

5 0

<em>The rate of change in the position</em> between any two moments in time can be calculated using position data. And the "rate of change in the position" is the velocity you're looking for.

Just read it out of the motion sensor and graph it up !

You might be interested in

An object of the same mass has three different weights at different times.

Sindrei [870]

Answer:

See below

Explanation:

Possible.....mass is the amount of matter an object has ....weight is the result of gravity on an object.... different gravity ( Earth , Moon or Mars etc)

results in different weights .

5 0

2 years ago

Scenario

zepelin [54]

Answer:

t = 23.255 s, x = 2298.98 m, v_y = - 227.90 m / s

Explanation:

After reading your extensive writing, we are going to solve the approach.

The initial speed of the plane is 250 miles / h and it is at an altitude of 2650 m; In general, planes fly horizontally for launch, therefore this is the initial horizontal speed.

As there is a mixture of units in different systems we are going to reduce everything to the SI system.

v₀ₓ = 250 miles h (1609.34 m / 1 mile) (1 h / 3600 s) = 111.76 m / s

y₀ = 2650 m

Let's set a reference system with the x-axis parallel to the ground, the y-axis is vertical. As time is a scalar it is the same for vertical and horizontal movement

Y axis

y = y₀ + v₀ t - ½ g t²

the initial vertical velocity when the cargo is dropped is zero and when it reaches the floor the height is zero

0 = y₀ + 0 - ½ g t²

t = $\sqrt{ \frac{2 y_o}{g} }$

t = √(2 2650/ 9.8)

t = 23.255 s

Therefore, for the cargo to reach the desired point, it must be launched from a distance of

x = v₀ₓ t

x = 111.76 23.255

x = 2298.98 m

at the point and arrival the speed is

vₓ = v₀ₓ = 111.76

vertical speed is

v_y = v_{oy} - gt

v_y = 0 - gt

v_y = - 9.8 23.25 555

v_y = - 227.90 m / s

the negative sign indicates that the speed is down

in the attachment we have a diagram of the movement

7 0

3 years ago

Jerome solves a problem using the law of conservation of momentum. What should Jerome always keep constant for each object after

s2008m [1.1K]

Jerome solves a problem using the law of conservation of momentum. What should Jerome always keep constant for each object after the objects collide and bounce apart?

a-velocity

b-mass

c-momentum

d-direction

Answer:

b. Mass

Explanation:

This question has to do with the principle of the law of conservation of momentum which states that the momentum of a system remains constant if no external force is acting on it.

As the question states, two objects collide with each other and eventually bounce apart, so their momentum may not be conserved but the mass of the objects is constant for each non-relativistic motion. Because of this, the mass of each object prior to the collision would be the same as the mass after the collision.

Therefore, the correct answer is B. Mass.

6 0

3 years ago

Read 2 more answers

in an experiment which the volume of dry sand is measured by the displacement of water, the sand was slightly wet to begin with.

Mamont248 [21]

It would mean that you could not know the precise volume of the sand. Only the volume of the sand plus the water that was making it damp.

In the experiments listed, the effects are easy to deduce by understanding that the water in the sand adds volume to the 'sample' being measured.

So in the case of calculating air space you would calculate <em>less</em> air space.

3 0

3 years ago

The equation for the speed of a satellite in a circular orbit around the earth depends on mass. Which mass?

katovenus [111]

<h3><u>Question: </u></h3>

The equation for the speed of a satellite in a circular orbit around the Earth depends on mass. Which mass?

a. The mass of the sun

b. The mass of the satellite

c. The mass of the Earth

<h3><u>Answer:</u></h3>

The equation for the speed of a satellite orbiting in a circular path around the earth depends upon the mass of Earth.

Option c

<h3><u> Explanation: </u></h3>

Any particular body performing circular motion has a centripetal force in picture. In this case of a satellite revolving in a circular orbit around the earth, the necessary centripetal force is provided by the gravitational force between the satellite and earth. Hence $F_{G} = F_{C}$ .