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podryga [215]
3 years ago
13

Where is potential energy in food stored

Physics
1 answer:
AlexFokin [52]3 years ago
6 0
The potential energy is stored in the chemical bonds of the food. When those bonds break up during the metabolic processes, the energy is released. After that, that energy is stored in the Adenosine Triphosphate bonds aka ATP. The simplest way to think is to think of food as the tightly bound atoms. When the chemical bonds between those atoms break, the stored energy in that food is released. 
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Convert time from 12-hour to 24-hour clock. ​
svet-max [94.6K]

Answer:

4:28

Explanation:

4:28am

a 12 hour clock continues going up after 12 (1:00pm=13:00). minutes stay the same. 12:00pm=00:00. this shows 4:28am, so you count 4 after 00:00.

6 0
3 years ago
The atomic number of a nucleus decreases during which nuclear reactions?
Goryan [66]
A related type of beta decay actually decreases the atomic number of the nucleus when a proton becomes a neutron. Due to charge conservation, this type of beta decay involves the release of a charged particle called a “positron” that looks and acts like an electron but has a positive charge.
5 0
3 years ago
Two blocks of ice, one four times as heavy as the other, are at rest on a frozen lake. A person pushes each block the same dista
qaws [65]

Answer:b

Explanation:

Given

mass of heavy object is 4m

mass of lighter object is m

A person pushes each block  with same force F

According to Work Energy theorem Change in kinetic energy of object is equal to Work done by all the object

As launching velocity is same for both the object so heavier mass must possess greater kinetic energy . For same force heavier mass must be pushed 4 times farther than the light block .

\Delta (K.E.)_H=\frac{1}{2}(4m)v^2

\Delta (K.E.)_L=\frac{1}{2}(m)v^2

\Delta K.E.=F\times d

So the correct option is b

4 0
3 years ago
A projectile is shot at an angle 45 degrees to the horizontalnear the surface of the earth but in the absence of air resistance.
juin [17]

Answer:

Explanation:

Given

For first case

launch angle \theta =45^{\circ}C

at highest point h=150 m/s

150=u\cos 45

u=\frac{150}{\cos 45}=212.132 m/s

For second case

\theta _2=37^{\circ}C

at highest Point velocity is u\cos \theta _2

=212.132\times \cos 37

=169.41 m/s

as there is no acceleration in x direction therefore horizontal velocity is same          

7 0
3 years ago
Read 2 more answers
The component of the external magnetic field along the central axis of a 78-turn circular coil of radius 34.0 cm decreases from
grigory [225]

Answer:

Induced current, I = 18.88 A

Explanation:

It is given that,

Number of turns, N = 78

Radius of the circular coil, r = 34 cm = 0.34 m

Magnetic field changes from 2.4 T to 0.4 T in 2 s.

Resistance of the coil, R = 1.5 ohms

We need to find the magnitude of the induced current in the coil. The induced emf is given by :

\epsilon=-N\dfrac{d\phi}{dt}

Where

\dfrac{d\phi}{dt} is the rate of change of magnetic flux,

And \phi=BA

\epsilon=-NA\dfrac{dB}{dt}

\epsilon=-78\times \pi (0.34)^2\dfrac{(0.4-2.4)}{2}

\epsilon=28.32\ V

Using Ohm's law, \epsilon=I\times R

Induced current, I=\dfrac{\epsilon}{R}

I=\dfrac{28.32}{1.5}

I = 18.88 A

So, the magnitude of the induced current in the coil is 18.88 A. Hence, this is the required solution.

5 0
3 years ago
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