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podryga [215]
3 years ago
13

Where is potential energy in food stored

Physics
1 answer:
AlexFokin [52]3 years ago
6 0
The potential energy is stored in the chemical bonds of the food. When those bonds break up during the metabolic processes, the energy is released. After that, that energy is stored in the Adenosine Triphosphate bonds aka ATP. The simplest way to think is to think of food as the tightly bound atoms. When the chemical bonds between those atoms break, the stored energy in that food is released. 
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anonymous 4 years ago The turbidity levels of water in four locations are shown in the table below. Which of these conclusions i
Tresset [83]
Hello!

The Correct Answer would 100% be:

Option "C".

"People in location C would complain about foul taste in water".

I Hope my answer has come to your Help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead! :)

(Mark As Brainliest IF Helped!)

-TheOneAboveAll :D
4 0
3 years ago
Read 2 more answers
Betty (mass 40 kg), standing on slippery ice, catches her leaping dog (mass 15 kg) moving horizontally at 3.0 m/s. Show that the
MA_775_DIABLO [31]

Answer:

v = 2.18m/s

Explanation:

In order to calculate the speed of Betty and her dog you take into account the law of momentum conservation. The total momentum before Betty catches her dog must be equal to the total momentum after.

Then you have:

Mv_{1o}+mv_{2o}=(M+m)v        (1)

M: mass Betty = 40kg

m: mass of the dog = 15kg

v1o: initial speed of Betty = 3.0m/s

v2o: initial speed of the dog = 0 m/s

v: speed of both Betty and her dog = ?

You solve the equation (1) for v:

v=\frac{Mv_{1o}+mv_{2o}}{M+m}=\frac{(40kg)(3.0m/s)+(15kg)(0m/s)}{40kg+15kg}\\\\v=2.18m/s

The speed fo both Betty and her dog is 2.18m/s

7 0
3 years ago
Listed in the Item Bank are some important labels for sections of the image below. To find out more information about labels, so
erica [24]

1 - cytoplasm

2 - DNA

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5 0
3 years ago
A 55-kg woman is wearing high heels.
Grace [21]

Answer:

Pressure, P=1.90\times 10^7\ Pa        

Explanation:

It is given that,

Mass of the woman, m = 55 kg

Diameter of the circular cross section, d = 6 mm

Radius, r = 3 mm = 0.003 m

Let P is the pressure exerted on the floor. It is equal to the force acting on woman per unit area. It is given by :

P=\dfrac{F}{A}

P=\dfrac{mg}{\pi r^2}

P=\dfrac{55\times 9.8}{\pi (0.003)^2}

P=1.90\times 10^7\ Pa

So, the pressure exerted on the floor is 1.90\times 10^7\ Pa. Hence, this is the required solution.

7 0
4 years ago
If I weighed 130 pounds what would my mass be in kilograms
lawyer [7]
You would weigh 58.967 kilograms
5 0
3 years ago
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