Answer:
cytoplasmic, transmembrane
Explanation:
Pulse chase experiment is an important technique used to analyze the cellular process by labeling the cells with radioactive compound.
The radioactive amino acids is injected into the rabbit's retina. Two different moving peaks are observed during the experiment. The first peak moved at 0.5-2 mm/day and second peak at 200-400 mm/day. These peaks are observed due to difference in the synthesis and transport rate of the protein. Cytoplasmic protein has slow transport and sorting rate, indicates the first peak. The second peak corresponds to transmembrane protein.
Thus, the correct answer is option (a).
The technique that is similar to EMDR is systematic desentization. It is a psychological therapy that is used as a treatment for anxiety disorders and phobias. It treats by exposing the patient to stimuli that provokes their disorders and were to on how to treat it as relaxed as possible after.
The Inland Rules specifies that red buoys must be passed on the
starboard side upon going upstream. The red buoys will mark the right side (starboard
side) at inbound direction. It should be placed on the left side (port side) of the channel when going outbound.
To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.
0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
The answers would be:
Layer D
Layer C
Layer B
Layer A
Layer E
Fault F
If you'd like to know why, here's more about the question:
The law of superpo sition states that the lower the layer, the older the rock is.
Looking at the layers alone, we can say that D is the oldest, and C would be next, so on and so forth.
The law of cross - cutt ing relationships, on the other hand, states that a geologic event, like a fault, is younger than the layer that it goes through.
So if we look at the figure given, the fault goes through all the layers, so we can say that it is younger than all the layers.
<em></em>
