Two parallel plates have equal but opposite charges on their surface. The plates are separated by a finite distance.
1 answer:
Answer:
(a) The speed of proton decreases as it moves from A to B.
(b) Plate B is at a higher potential.
(c) Plate B is positive, plate A is negative.
(d) Parallel lines parallel to the two plates.
Parallel lines equally spaced.
Explanation:
The electric potential energy is given by the following formula:
Alternatively, potential energy in a uniform electric field is
where 'r' is the distance from negative to positive plates. This definition is analogues to that of gravitational potential energy, U = mgh.
If the positively charged proton is gaining potential energy as it gets closer to plate B, then plate B is charged positively.
(a) According to this information, the speed of proton decreases as it moves from A to B. This is similar to the speed of an object which is gaining potential energy by moving higher.
(b) By the same gravitational analogy, plate B is at a higher potential.
(c) As explained before, Plate A is negative and Plate B is positive.
(d) The equipotential lines are parallel to electric field lines which are perpendicular to the plates. So, the equipotential lines are parallel to the plates. Since the electric field between the plates is uniform, then the equipotential lines are equally seperated.
You might be interested in
Answer:
c) The distance between the balls increases.
Explanation:
If you drop the balls at the same time, regardless of their masses they accelerate equally, since they will be in free fall.
However, if you drop one of the balls earlier, then that ball will gain velocity, whereas the second ball has zero initial velocity. At the time the second ball is dropped, both balls have the same acceleration but different initial velocities.
According to the below kinematics equation:
The initial velocity of the first ball will make the difference, and the first ball will travel a greater distance than the second ball. Hence, their distance increases.