Answer:
A) 6.5 m/s²
Explanation:
Mass of the bucket, m = 3.0 kg
depth of the well, d = 10 m
tension on the rope, T = 9.8 N
The net downward force on the bucket is given as;
T = mg - ma
where;
a is downward acceleration of the bucket
9.8 = (3 x 9.8) - 3a
9.8 = 29.4 - 3a
3a = 29.4 - 9.8
3a = 19.6
a = 19.6 / 3
a = 6.53 m/s² downwards
Therefore, the acceleration of the bucket is 6.53 m/s² downwards
Answer:
The minimum frequency of the coil is 7.1 Hz
Explanation:
Given;
number of turns, N = 200 turns
cross sectional area, A = 300 cm² = 300 x 10⁻⁴ m²
magnitude of magnetic field strength, B = 30 x 10⁻³ T
maximum value of the induced emf, E = 8 V
Maximum induced emf is given as;
E = NBAω
where
ω is angular velocity (ω = 2πf)
E = NBA2πf
where;
f is the minimum frequency, measured in hertz (Hz)
f = E / (NBA2π)
f = 8 / (200 x 30 x 10⁻³ x 300 x 10⁻⁴ x 2 x 3.142)
f = 7.073 Hz
f = 7.1 Hz
Therefore, the minimum frequency of the coil is 7.1 Hz
The correct answer is the one with 45000 kg*km/hr.
the formula is p = m*v
900 *50/hr giving u 45000
I know this is the correct answer because i have already turned it in and got a 100%.
Answer:
156.8 Watts
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 10 kg
Height (h) = 8 m
Time (t) = 5 s
Power (P) =?
Next, we shall determine the energy used by the motor to raise the block. This can be obtained as follow:
Mass (m) = 10 kg
Height (h) = 8 m
Acceleration due to gravity (g) = 9.8 m/s²
Energy (E) =?
E = mgh
E = 10 × 9. 8 × 8
E = 784 J
Finally, we shall determine the power output of the motor. This can be obtained as illustrated below:
Time (t) = 5 s
Energy (E) = 784 J
Power (P) =?
P = E/t
P = 784 / 5
P = 156.8 Watts
Therefore, the power output of the motor is 156.8 Watts
Answer:
1225 J
Explanation:
The Gravitational potential energy (PEG) gained by a mass lifted above the ground is given by
where
m is the mass
g = 9.8 m/s^2 is the acceleration due to gravity
h is the height at which the object has been lifted
In this problem, we have
m = 250 kg
h = 0.5 m
So, the PE of the object is
