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mrs_skeptik [129]
3 years ago
13

250 at 5% simple interest for 3 years

Mathematics
1 answer:
koban [17]3 years ago
5 0
787.50

You multiply 250 by .05 to get 12.50, then you add it to 250 to get 262.50, and multiply it by 3 to get 787.50
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GaryK [48]

shovels=3

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8 0
2 years ago
By taking  = 3.141 and
Whitepunk [10]

The value of the expression 1/√2 + π where the given parameters are π = 3.141 and  √2 = 1.414 is 3.848

<h3>How to evaluate the expression?</h3>

The given parameters are

π = 3.141

√2 = 1.414

The expression to evaluate is given as:

1/√2 + π

Start by substituting π = 3.141 and √2 = 1.414 in the expressions 1/√2 + π

1/√2 + π = 1/1.414 + 3.141

Evaluate the quotient

1/√2 + π = 0.707 + 3.141

Evaluate the sum

1/√2 + π = 3.848

Hence, the value of the expression 1/√2 + π where the given parameters are π = 3.141 and  √2 = 1.414 is 3.848

Read more about expressions at:

brainly.com/question/723406

#SPJ1

<u>Complete question</u>

By taking π = 3.141 and √2 = 1.414, evaluate 1/√2 + π up to three places of decimals.

8 0
1 year ago
7. You have $2 worth of quarters, dimes, and nickels
Doss [256]

Answer:

6 quarters, 4 dimes, and 2 nickels

5 0
2 years ago
Read 2 more answers
Simplify the expression given below. x+2/4x^2+5x+1 * 4x+1/x^2-4
GenaCL600 [577]

Answer:

\frac{1}{(x+1)(x-2)}

Step-by-step explanation:

\frac{x+2}{4x^2 + 5x + 1} \ \times \ \frac{4x+1}{x^2-4}\\\\=\frac{x+2}{4x^2 + 4x  + x + 1} \ \times \ \frac{4x+1}{x^2-2^2}\\\\=\frac{x+2}{4x(x + 1)  + 1( x + 1)} \ \times \ \frac{4x+1}{(x - 2)(x + 2)}    \ \ \ \ \  \ \ \ [ \ (a^2 - b^2 = (a-b)(a+b) \ ]\\\\\\=\frac{x+2}{(4x + 1)(x+1)} \ \times \ \frac{4x+1}{(x-2)(x+2)}\\\\=\frac{1}{(x+1)} \ \times \ \frac{1}{(x-2)}\\\\= \frac{1}{(x+1)(x-2)}

8 0
2 years ago
What is the domain of the function on the graph?
hammer [34]

Answer:

Option (4)

Step-by-step explanation:

Domain:

Domain of function is defined by the x-values (Input values) on the graph.

Range:

Range of a function is defined by the y-values (output values) on the graph.

From the graph attached,

x-values are starting from (-3) to infinity.

Therefore, domain of the function will be all real numbers greater than equal to (-3).

Option (4) will be the answer.

4 0
3 years ago
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