The notation would be O (n-1) because there would be no need to compare with the first bit however this notation is most commonly noted as O (n) but the first is also technically correct
Complete Question:
Write statements that output variable numComputers as follows. End with a newline. There are 10 computers.
#include <iostream>
using namespace std;
int main()
{
int numComputers;
cin >> numComputers; // Program will be tested with values: 10.
...
return 0;
}
Answer:
cout << "There are ";
cout << numComputers;
cout << " computers." << "\n";
Explanation:
Using three cout statements the string "There are 10 computers." is printed out, notice that the variable numComputers is entered by the user when the program is run. Another way of concatenating an integer variable and string for printout is by the use of the + (plus) operator.
StrawberryTeaa (could be any fruit: blueberry, peach, etc)
potatoxchip
pastelsquid
SquishyPeach
GummiBear
ElegantFlaws (could add an e and remove the s: EleganteFlaw)
hunnie_b (or honee, honnie, hunni, etc)
agonyisheree
It's cool if you don't like these. I had trouble when I changed my user too. But you'll find your perfect username eventually. :)
Answer:
4 5 6
Explanation:
Since there is a do-while loop, you need to check the values for each iteration until the condition (Count <= X) is not satisfied.
First iteration -> Count = 1 and X = 3, Y = 1 + 3, Write Y -> 4
Second iteration -> Count = 2 and X = 3, Y = 2 + 3, Write Y -> 5
Third iteration -> Count = 3 and X = 3, Y = 3 + 3, Write Y -> 6
After the third iteration count is equal to 4 and X is equal to 3. That is why loop ends.
2. on the file menu, click new, and then click blank presentation.
