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Scorpion4ik [409]

4 years ago

8

This is the balances equations. C3H8 + 5O2 → 3CO2 + 4H2O How many moles of oxygen are required to produce 37.15 g CO2

1 answer:

AleksandrR [38]4 years ago

4 0

Molar mass O2 = 31.99 g/mol

Molar mass CO2 = 44.01 g/mol

Moles ratio:

<span>C3H8 + 5 O2 = 3 CO2 + 4 H2O
</span>
5 x 44.01 g O2 ---------------- 3 x 44.01 g CO2
( mass of O2) ------------------ 37.15 g CO2

mass of O2 = 37.15 x 5 x 44.01/ 3 x 44.01

mass of O2 = 8174.8575 / 132.03

mass of O2 = 61.916 g

Therefore:

1 mole O2 ----------------- 31.99 g
moles O2 -------------------- 61.916

moles O2 = 61.916 x 1 / 31.99

moles = 61.916 / 31.99 => 1.935 moles of O2

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Explain why organic reactions occur at a slower rate than inorganic reactions. What do chemists use to speed these reactions up?

8_murik_8 [283]

The organic particles are molecules. Because of strong covalent bonding in the molecule, organic compounds do not react quickly. Reactions with organic compounds are generally slower than inorganic reactions due to this fact.

Increasing temperature speeds up a reaction because of there being more collisions and those collisions have higher energy. Also the high concentration of the chemicals, particle size and there being a suitable catalyst present. ( Though this process is harmful should it be used in modifying results in food grains and meats.)

5 0

3 years ago

For the reaction 2Co3+(aq)+2Cl−(aq)→2Co2+(aq)+Cl2(g). E∘=0.483 V what is the cell potential at 25 ∘C if the concentrations are [

sveta [45]

Explanation:

The given data is as follows.

$E^{o}$ = 0.483, $[Co^{3+}]$ = 0.173 M,

$[Co^{2+}]$ = 0.433 M, $[Cl^{-}]$ = 0.306 M,

$P_{Cl_{2}}$ = 9.0 atm

According to the ideal gas equation, PV = nRT

or, P = $\frac{n}{V}RT$

Also, we know that

Density = $\frac{mass}{volume}$

So, P = MRT

and, M = $\frac{P}{RT}$

= $\frac{9.0 atm}{0.0820 L atm/mol K \times 298 K}$

= $\frac{9.0}{24.436}$

= 0.368 mol/L

Now, we will calculate the cell potential as follows.

E = $E^{o} - \frac{0.0591}{n} log \frac{[Co^{2+}]^{2}[Cl_{2}]}{[Co^{3+}][Cl^{-}]^{2}}$

= $0.483 - \frac{0.0591}{2} log \frac{(0.433)^{2}(0.368)}{(0.173)(0.306)^{2}}$

= $0.483 - 0.02955 log \frac{0.0689}{0.0162}$

= $0.483 - 0.02955 \times 0.628$

= 0.483 - 0.0185

= 0.4645 V

Thus, we can conclude that the cell potential of given cell at $25^{o}C$ is 0.4645 V.

4 0

4 years ago

How many moles are in 43.5 g of sodium hydroxide (NaOH)?

Makovka662 [10]

Answer:

1.09 moles of NaOH

Explanation:

First of all, to calculate moles, you need to find the molar mass of NaOH.

Let us first find the molar mass of NaOH then.

Na = 23.0 amu

O = 16.0

H = 1.0

They are 1 nitrogen atom, 1 oxygen atom, and one hydrogen atom.

So do this.

23.0(1) + 16.0(1) + 1.0(1) = 40 g/mol.

Now use dimensional analysis to show your work

43.5 g of NaOH * 1 mol of NaOH / 40 g/mol of NaOH

The grams cancel out.

43.5 / 40.0 = 1.0875

Use sig figs and round the answer to the nearest hundredths place.

1.0875 = 1.09

So the final answer is 1.09 moles of NaOH

Hope it helped!

3 0

3 years ago

Four students measure the length of a paper clip whose actual length is 3.2 cm. whose measurements are precise but not accurate?

Bingel [31]

Answer:

A. Samuel

Explanation:

although he is not right he gets the same measurement several times

8 0

4 years ago

Read 2 more answers

Order frome largest to smallest <br>Allele,<br>Chromosome,<br>DNA, <br>nucleus of a cell

svetlana [45]

Allele, dna, chromosome, nucleus of a cell

5 0

3 years ago