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scoundrel [369]
4 years ago
7

How are changes between phases consistent with the law of conservation of matter

Chemistry
2 answers:
Arada [10]4 years ago
8 0
<span>I'm assuming its cause the total mass is the same, changes between phases are physical... solid ice and liquid water have the same mass</span>
ikadub [295]4 years ago
5 0

Answer:

When a substance change its phase, neither destruction nor creation of matter is carried out.

Explanation:

Hello,

In this case, a phase change or phase transition is a physical process based on a modification of a substance's molecular arrangement due to the heat adding or removal, in such a way, if for instance a liquid is boiled, heat is added so matter is not destroyed but changed in its molecular arrangement from more organized and quiet, to dispersed and choppy. A similar phenomena also occurs to other phase transition, therefore, one concludes that when a substance change its phase, neither destruction nor creation of matter is carried out so the law of conservation of matter is respected.

Best regards.

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What states can electrons exist in
Norma-Jean [14]

Electrons does not have state like matter of Solid, liquid, gas or plasma states. Electrons together with other molecular and atom components makes up matter. Their characteristic and elemental inclination determines the state for which the matter will exist in.

8 0
4 years ago
2. The Food and Drug Administration (FDA) mandates that all vinegar sold in the United States must have a minimum concentration
Scilla [17]

Answer:

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

Explanation:

4% acetic acid by mass means that 4 gram of acetic acid in 100 g solution.

Given that density of the vinegar is same is that of water =  1 g/mL

Mass of the vinegar solution = 100 g

Volume of the vinegar solution = V

Density=\frac{Mass}{Volume}

1 g/mL=\frac{100 g}{V}

V = 100 mL = 0.1 L

Moles of acetic acid =\frac{4 g}{60.052 g/mol}=0.0666 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution(L)}}

M=\frac{0.0666 mol}{0.1 L}=0.6660 mol/L

The minimum molarity of acetic acid in vinegar according to given standards is 0.6660 mol/L.

4 0
4 years ago
Where does the energy for almost all ecosystems come from
bonufazy [111]

The Sun is the major source of energy for organisms and the ecosystems of which they are a part. Producers such as plants, algae, and cyanobacteria use the energy from sunlight to make organic matter from carbon dioxide and water. This establishes the beginning of energy flow through almost all food webs.

4 0
3 years ago
Potassium is isotopic and has RAM of 39.5 work out the percentage abundance of each isotope in a given sample of potassium which
Troyanec [42]

Yo sup??

Let the percentage of K-39 be x

then the percentage of K-40 is 100-(x+0.01)

We know that the net weight should be 39.5. Therefore we can say

(39*x+40*(100-(x+0.01))+38*0.01)/100=39.5  

(since we are taking it in percent)

39*x+40*(100-(x+0.01))+38*0.01=3950

39x+4000-40x-0.4+0.38=3950

2x=49.98

x=24.99

=25 (approx)

Therefore K-39 is 25% in nature and K-40 is 75% in nature.

Hope this helps.

3 0
3 years ago
The British gold sovereign coin is an alloy of gold and copper having a total mass of 7.988 g, and is 22-karat gold.
azamat

Answer:

(a) m_{gold}=7.322g

(b)

V_{gold}=0.379cm^3

V_{copper}=0.122cm^3

(c) \rho _{coin}=15.94g/cm^3

Explanation:

Hello,

(a) In this case, with the given formula we easily compute the mass of gold contained in the sovereign  as shown below:

m_{gold}=\frac{m_{tota}*karats}{24}=\frac{7.988g*22}{24}=7.322g

(b) Now, by knowing the density of gold and copper, 19.32 and 8.94 g/cm³ respectively, we compute each volume, by also knowing that the rest of the coin contains copper:

V_{gold}=\frac{m_{gold}}{\rho_{gold}} =\frac{7.322g}{19.32g/cm^3}=0.379cm^3

m_{copper}=7.988g-7.322g=1.09g\\V_{copper}=\frac{m_{copper}}{\rho_{copper}}=\frac{1.09g}{8.94g/cm^3}  \\\\V_{copper}=0.122cm^3

(c) Finally, the volume is computed by dividing the total mass over the total volume containing both gold and copper:

\rho _{coin}=\frac{m_{total}}{V_{gold}+V_{copper}}=\frac{7.988 g}{0.379cm^3+0.122cm^3}\\  \\\rho _{coin}=15.94g/cm^3

Best regards.

3 0
3 years ago
Read 2 more answers
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