Answer:
Joule-Thomson coefficient for an ideal gas:

Explanation:
Joule-Thomson coefficient can be defined as change of temperature with respect to pressure at constant enthalpy.
Thus,
![\mu_{J.T} = \left [\frac{\partial T}{\partial P} \right ]_H](https://tex.z-dn.net/?f=%5Cmu_%7BJ.T%7D%20%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20T%7D%7B%5Cpartial%20P%7D%20%5Cright%20%5D_H)
Also,


![dH= \left [\frac{\partial H}{\partial T}\right ]_P dT + \left [\frac{\partial H}{\partial P}\right ]_T dT](https://tex.z-dn.net/?f=dH%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20T%7D%5Cright%20%5D_P%20dT%20%2B%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20dT)
Also,
is defined as:
![C_p = \left [\frac{\partial H}{\partial T}\right ]_P](https://tex.z-dn.net/?f=C_p%20%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20T%7D%5Cright%20%5D_P)

![dH= C_p dT + \left [\frac{\partial H}{\partial P}\right ]_T dT](https://tex.z-dn.net/?f=dH%3D%20C_p%20dT%20%2B%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20dT)
Acoording to defination, the ethalpy is constant which means 

![\left [\frac{\partial H}{\partial P}\right ]_T = -C_p\times \left [\frac{\partial T}{\partial P}\right ]_H](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20%3D%20-C_p%5Ctimes%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20T%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_H)

![\mu_{J.T} = \left [\frac{\partial T}{\partial P}\right ]_H](https://tex.z-dn.net/?f=%5Cmu_%7BJ.T%7D%20%3D%20%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20T%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_H)

![\left [\frac{\partial H}{\partial P}\right ]_T =-\mu_{J.T}\times C_p](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20%3D-%5Cmu_%7BJ.T%7D%5Ctimes%20C_p)
For an ideal gas,
![\left [\frac{\partial H}{\partial P}\right ]_T = 0](https://tex.z-dn.net/?f=%5Cleft%20%5B%5Cfrac%7B%5Cpartial%20H%7D%7B%5Cpartial%20P%7D%5Cright%20%5D_T%20%3D%200)
So,

Thus,
≠0. So,

Answer is A. The reason to create such is to conduct electricity, and metal conducts electricity.
Hope this helps, Tiara
Answer:
2.318032g
Explanation:
-The electrolysis equation of water is written as below:

-The mole ratio of Water to the hydrogen formed is 1:1, therefore 2.3 moles of hydrogen gas is produced.
-Hydrogen's molar mass is 1.00784 grams:

Hence, 2.318032 grams of hydrogen is produced.
Answer:
Explanation:
Examples of pure substances include tin, sulfur, diamond, water, pure sugar (sucrose), table salt (sodium chloride) and baking soda (sodium bicarbonate). Crystals, in general, are pure substances. Tin, sulfur, and diamond are examples of pure substances that are chemical elements.