All categories

3 years ago

WWW 7. What is the subscript for Hydrogen?

1 answer:

4 0

Answer: In the chemical formula for water, the subscript for hydrogen is 2. Notice that the 2 is smaller and written slightly below the H and O. It is called a subscript because it is written ("script") "below" ("sub") the preceding letter.

Explanation:

You might be interested in

Consider the reaction N2(g) + 3H2(g) → 2NH3(g) Suppose that at a particular moment during the reaction, molecular hydrogen is re

rosijanka [135]

Answer:

The solution to the question is as follows

(a) The rate of ammonia formation = 0.061 M/s

(b) the rate of N₂ consumption = 0.0303 M/s

Explanation:

(a) To solve the question we note that the reaction consists of one mole of N₂ combining with three moles of H₂ to form 2 moles of NH₃

N₂(g) + 3H₂(g) → 2NH₃(g)

The rate of reaction of molecular hydrogen = 0.091 M/s, hence we have

3 moles of H₂ reacts to form 2 moles of NH₃, therefore

0.091 M of H₂ will react to form 2/3 × 0.091 M or 0.061 M of NH₃

Hence the rate of ammonia formation is 0.061 M/s

(b) From the reaction equation we have 3 moles of H₂ and one mole of N₂ being consumed at the same time hence

0.091 M of H₂ is consumed simultaneously with 1/3 × 0.091 M or 0.0303 M of N₂

Therefore the rate of consumption of N₂ = 0.0303 M/s

6 0

3 years ago

In a comparison of metals to nonmetals,metals tend to have

Georgia [21]

They conduct electricity. They tend to have conductors of electricity.

3 0

4 years ago

Is a burning log an exothermic or endothermic event if the log is the system?

ziro4ka [17]

Yes it is a exothermic reaction.

7 0

3 years ago

Read 2 more answers

Describe in detail how to prepare 500.0 mL of a 2.5 M calcium chloride solution. Calcium chloride is purchased as a solid. TO pi

antoniya [11.8K]

Answer:

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the solute gets completely soluble add more water up till the mark of 500 ml.

Explanation:

Concentration of calcium chloride = 2.5 M

Volume of the solution = 500.0 ml = 0.5000 L

Moles of calcium chloride = n

$c=\frac{n}{V(L)}$

n = moles of solute

c = concentration of solution

V = volume of the solution in L

$2.5 M=\frac{n}{0.5000 L}$

$n=2.5 M\times 0.5000 L = 1.2500 mol$

$n=\frac{\text{Mass of calcium chloride}}{\text{Molar mass of calcium chloride}}$

$1.2500 mol=\frac{\text{Mass of calcium chloride}}{111 g/mol}$

Mass of calcium chloride = 111 g/mol × 1.2500 mol = 138.75 g

In a volumetric flask of marking 500.0 mL add 138.75 grams of calcium chloride and add small amount of water to dissolve solute completely. After the the solute gets completely soluble add more water up till the mark of 500 ml.

4 0

3 years ago

I need help with this question!!!

ehidna [41]

Answer:

its c

Explanation:

5 0

3 years ago