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2 years ago

Use the information and table to answer the following question.

Chemistry

2 answers:

Feliz [49]2 years ago

4 0

Answer:

Explanation:

are you doing your mid term?well i got c

bixtya [17]2 years ago

4 0

Answer:

Explanation:

Compounds 1 and 3 are lonic.Because ionic compounds are composed of oppositely charged ions that are attracted to one another,

they require more energy to melt than covalent bonds. just usign he process of elimination you get rid of A and B becuase covalant compound contaIN same negatively charged particles that contain requrie less energy to melt and since two and four have low melting point its d

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2 years ago

Which best describes a compound such as sodium chloride?

finlep [7]

Answer:

It s a pure substance.

Explanation:

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2 years ago

Where is ocean water the densest?

Vika [28.1K]

Answer:

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Explanation:

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2 years ago

A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?

neonofarm [45]

Answer:

$\boxed {\boxed {\sf 40.4299 \ Joules}}$

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

$PE= m \times g \times h$

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

m= 1.85 kg
g= 9.8 m/s²
h= 2.23 m

Substitute the values into the formula.

$PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m$

Multiply the first 2 numbers together.

$PE=18.13 \ kg*m/s^2 *2.23 \ m$

Multiply again.

$PE= 40.4299 \ kg*m^2/s^2$

1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

$PE= 40.4299 \ J$

The textbook has <u>40.4299 Joules of potential energy.</u>

7 0

2 years ago

What is the next atomic orbital in the series 1s 2p 3s 3p

liq [111]

Answer:

s an example, the ground state configuration of the sodium atom is 1s22s22p63s1, as deduced from the Aufbau principle (see below). The first excited state is obtained by promoting a 3s electron to the 3p orbital, to obtain the 1s22s22p63p1 configuration, abbreviated as the 3p level.

Explanation:

3 0

2 years ago

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