Use the information and table to answer the following question.
2 answers:
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Answer:
The estimated feed rate of logs is 14.3 logs/min.
Explanation:
The product of the process is 2000 tons/day of dry wood pulp, of 85 wt% of cellulose. That represents (2000*0.85)=1700 tons/day of cellulose.
That cellulose has to be feed by the wood chips, which had 47 wt% of cellulose in its composition. That means you need (1700/0.47)=3617 tons/day of wood chips to provide all that cellulose.
Th entering flow is wood chips with 45 wt% of water. This solution has an specific gravity of 0.640.
To know the specific gravity of the wood chips we have to write a volume balance. We also know that Mw=0.45*M and Mc=0.55*M.
The specific gravity of the wood chips is 0.494.
The average volume of a log is
The weight of one log is
To provide 3617 ton/day of wood chips, we need
The feed rate of logs is 14.3 logs/min.
Answer : The work done on the surroundings is, 709.1 Joules.
Explanation :
The formula used for isothermally irreversible expansion is :
where,
w = work done
= external pressure = 1.00 atm
= initial volume of gas = 1.00 L
= final volume of gas = 8.00 L
Now put all the given values in the above formula, we get :
The work done by the system on the surroundings are, 709.1 Joules. In this, the negative sign indicates the work is done by the system on the surroundings.
Therefore, the work done on the surroundings is, 709.1 Joules.