Calculate the H positive from the pH equation: pH equals -log (H positive). This would be 10 to the -6.49. Let's call the acid HA. To calculate Ka in this equation, Ka equals H positive times A- over HA. HA is going to be the 0 0121. So, Ka=(10^-6.49)^2/0.0121. This equals 1.05*10^-13/0.0121. Ka then equals 8.65*10^-12.
Answer:
D
Explanation:
D. V1P1 / T1=V2P2 / T2 is correct
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Hey there :
Molar mass of NaCl = 58.44 g/mol
Number of moles :
n = mass of solute / molar mass
n = 58 / 58.44
n = 0.9924 moles of NaCl
Volume = 1.0 L
Therefore:
Molarity = number of moles / volume ( L )
Molarity = 0.9924 / 1.0
Molarity = 0.9924 M
Hope that helps!
