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3 years ago

Measure the mass of a truckful of grain, use:

Chemistry

2 answers:

Nimfa-mama [501]3 years ago

8 0

Answer:

tons

Explanation:

Mars2501 [29]3 years ago

3 0

The answer is Tons

Hope This helps you out :D

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A student collects 25 mL of gas at 0.98 bar. What volume would this gas occupy at 1.013 bar? * 3 points 25.8 mL 24.2 mL .09 mL 3

trasher [3.6K]

Answer:

24.2 mL.

Explanation:

<em>Assuming constant temperature</em>, we can solve this problem using <em>Boyle's law</em>, which states:

P₁V₁=P₂V₂

Where:

P₁ = 0.98 bar

V₁ = 25 mL

P₂ = 1.013 bar

V₂ = ?

We <u>input the data</u>:

0.98 bar * 25 mL = 1.013 bar * V₂

And <u>solve for V₂</u>:

V₂ = 24.18 mL

The closest option is the second one: 24.2 mL.

3 0

3 years ago

ZILLDIFFEQMODAP11 3.1.021. My Notes Ask Your Teacher A tank contains 150 liters of fluid in which 10 grams of salt is dissolved.

SSSSS [86.1K]

Answer:

Therefore, the number of grams of salt in the tank at time t is $A(t) = 150-140 e^{-\frac{t}{30} }$

Explanation:

Given:

Tank A contain $V_{1} = 150$ lit

Rate $\alpha = 5 \frac{L}{min}$

Dissolved salt $A = 10$ gm

Salt pumped in one minute is $4 \frac{L}{min}$

Salt pumped out is $\frac{5L}{150L} = \frac{1}{30}$ of initial amount added salt.

To find $A(t)$

$\frac{dA}{dt} = Rate _{in} - Rate _{out}$

$A' = 5 - \frac{A}{30}$

$A' + \frac{A}{30} = 5$

Solving above equation,

$I .F = e^{\int\limits {p} \, dt }$

$y = e^{\int\limits {\frac{1}{30} } \, dt }$

$y = e^{\frac{t}{30} }$

$(Ae^{\frac{t}{30} } )' = 5 e^{\frac{t}{30} } + c$

Integrating on both side,

$Ae^{\frac{t}{30} } = 5 \times 30 e^{\frac{t}{30} } +c$

Add $e^{-\frac{t}{30} }$ on above equation,

$A = 150 + ce^{-\frac{t}{30} }$

Here given in question, $A(t=0) = 10$

$10 =150 +c$

$c = -140$

Put value of constant in above equation, and find the number of grams of salt in the tank at time t.

$A(t) = 150-140 e^{-\frac{t}{30} }$

Therefore, the number of grams of salt in the tank at time t is $A(t) = 150-140 e^{-\frac{t}{30} }$

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3 years ago

Where can you find most of earth's freshwater?

rjkz [21]

The answer is A, underground

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3 years ago

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WHAT IN THE WORLD IS THIS?

AveGali [126]

Answer:

Explanation:

Nothing but the D

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3 years ago

What is the freezing point of an aqueous suger (C12H22O11) solution that boils at 110C°?

AURORKA [14]

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

<h3>What is the freezing point?</h3>

The temperature at which a liquid solidifies.

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

Learn more about the freezing point here:

brainly.com/question/3543605

#SPJ1

7 0

2 years ago