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Neporo4naja [7]
3 years ago
13

Energy process consistent with the conservation of energy and conservation of mass principles can actually occur in nature. a)-T

rue b)-False
Engineering
1 answer:
Ksivusya [100]3 years ago
7 0

Answer:

True

Explanation:

in a lightning for example we can see energy flowing in the environment.

The most easy way of seeing this is with the evaporation of the water in the sea because of the energy coming from the sun, the energy is used to change the state of the matter in water, changing it from liquid to gas. The energy is conservated and used for the environment.

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A good rule of thumb is to design the horizontal stabilizer so that its area is about 1/6 to 1/8 of the area of the wing. If the
erik [133]

Answer:

Stabilizer with area = 14 cm2

Explanation:

i dont know why but its right

4 0
4 years ago
An overhead 25m long, uninsulated industrial steam pipe of 100mm diameter is routed through a building whose walls and air are a
DedPeter [7]

Answer:

a) he rate of heat loss from the steam line is 18.413588 kW

b) the annual cost of heat loss from line is $12904.25

Explanation:

a)

first we find the area

A = πdL

d is the diameter (0.1m) and L is the length (25m)

so

A = π ×  0.1 × 25

A = 7.85 m²

Now rate of heat loss through convection

qconv = hA(Ts -Ta)

h is the convective heat transfer coefficient (10 W/m²K), Ts is surface temperature (150°), Ta is temperature of air (25°)

so we substitute

qconv = 10 W/m²K × 7.85 m² × ( 150° - 25°)

qconv = 9817.477 J/s

Now heat lost through radiation

qrad = ∈Aα ( Ts⁴ - Ta⁴)

∈ is the emissivity (0.8), α is the boltzmann constant ( 5.67×10⁻⁸m⁻²K⁻⁴ ),

first we shall covert our temperatures from Celsius to kelvin scale

Ts is surface temperature (150 + 273K ), Ta is temperature of air (25 + 273K)

so we substitute

qrad = 0.8 × 7.854 × 5.67×10⁻⁸ × ( (423)⁴ - (298)⁴ )

qrad = 3.5625×10⁻⁷ × 2.413×10¹⁰

qrad = 8596.112 J/s

Now to get the total rate of heat loss through convection and radiation, we say

q = qconv + qrad

q = 9817.477 + 8596.112

q = 18413.588 J/s ≈ 18.413588 kW

Therefore the rate of heat loss from the steam line is 18.413588 kW

b)

annual cost of heat lost rate

A = C × q/n × ( 3600 × 24 × 365 )

C is the cost of heat per MJ( $0.02/10⁶) n is broiler efficiency ( 0.9)

so we substitute

A = 0.02/10⁶  × 18413.588/0.9 × ( 3600 × 24 × 365 )

A = $12904.25

Therefore the annual cost of heat loss from line is $12904.25

4 0
4 years ago
What is the importance of knowing the parts and function of the ignition system in servicing your own vehicle
lisov135 [29]

Answer:

El conocer la función del sistema nervioso permite comprender la estructura del cuerpo. Puesto que, toda acción que se se realice en ella dependerá del sistema nervioso para que sea eficaz

4 0
2 years ago
Water from a stationary nozzle impinges on a moving vane with turning angle θ = 120. The vane moves away from the nozzle with co
Tems11 [23]

Answer:

The force that must be applied to maintain the vane speed constant is 2771.26 N

Explanation:

Given;

turning angle of the vane = 120°

control volume velocity, u = 10 m/s

absolute velocity, v = 30 m/s

nozzle area = 0.004 m²

The force acting on the vane has horizontal and vertical components:

Based on Reynolds general control volume system;

The horizontal force component of the system, ∑Fₓ = ρW²A(1-cosθ)

where;

ρ is the density of water = 1000 kg/m³

W is the relative velocity = Absolute velocity - control volume velocity

W = v - u

    = 30 - 10 = 20m/s

∑Fₓ = ρW²A(1-cosθ) = 1000 x 20² x 0.004 (1 - cos 120) = 2400 N

The vertical force component of the system, ∑Fy = ρW²A(sinθ)

∑Fy = ρW²A(sinθ) = 1000 x 20² x 0.004 x sin(120) = 1385.6 N

The magnitude of the force applied = \sqrt{F_x^2 + F_y^2}

F = \sqrt{2400^2 + 1385.6^2} = 2771.26 \ N

The force that must be applied to maintain the vane speed constant is 2771.26 N

6 0
3 years ago
Read 2 more answers
A 60-kg woman holds a 9-kg package as she stands within an elevator which briefly accelerates upward at a rate of g/4. Determine
Anuta_ua [19.1K]

Answer:

force R = 846.11 N

lifting force L = 110.36 N

if cable fail complete both R and L will be zero

Explanation:

given data

mass woman mw = 60 kg

mass package mp = 9 kg

accelerates rate a = g/4

to find out

force R and lifting force L and if cable fail than what values would R and L acquire

solution

we calculate here first reaction R force

we know elevator which accelerates upward

so now by direction of motion , balance the force that is express as

R - ( mw + mp ) × g = ( mw + mp ) × a

here put all these value and a = g/4 and use g = 9.81 m/s²

R - ( 60 + 9 ) × 9.81 = ( 60 + 9  ) × g/4

R = ( 69  ) × 9.81/4  + ( 69 ) 9.81

R = 69  ( 9.81 + 2.4525 )

force R = 846.11 N

and

lifting force is express as here

lifting force = mp ( g + a)

put here value

lifting force = 9 ( 9.81 + 9.81/4)

lifting force L = 110.36 N

and

we know if cable completely fail than body move free fall and experience no force

so both R and L will be zero

5 0
3 years ago
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