Answer:
second-law efficiency = 62.42 %
Explanation:
given data
temperature T1 = 1200°C = 1473 K
temperature T2 = 20°C = 293 K
thermal efficiency η = 50 percent
solution
as we know that thermal efficiency of reversible heat engine between same temp reservoir
so here
efficiency ( reversible ) η1 = 1 -
............1
efficiency ( reversible ) η1 = 1 -
so efficiency ( reversible ) η1 = 0.801
so here second-law efficiency of this power plant is
second-law efficiency =
second-law efficiency =
second-law efficiency = 62.42 %
Answer:
So % increment in tool life is equal to 4640 %.
Explanation:
Initially n=0.12 ,V=130 m/min
Finally C increased by 10% , V=90 m/min
Let's take the tool life initial condition is
and when C is increased it become
.
As we know that tool life equation for tool

At initial condition
------(1)
At final condition
-----(2)
From above equation


So increment in tool life =
=
So % increment in tool life is equal to 4640 %.
Answer:
Explanation:
4140-40 I’d pick wood
I hope this helps! :)
Answer: Combustion of Hydrocarbons
Explanation:
The Independent variable in an experiment is the one whose effect on the dependent variable is being measured. The independent variable therefore is controlled to see the effect it will have in the experiment.
In this experiment, the scientists combusted different types of hydrocarbons (diesel, gasoline, natural gas and a gasoline/ethanol mixture) as they aimed to find out the effect that this burning would have on the environment thereby making the combustion of hydrocarbons the independent variable.