Water from a stationary nozzle impinges on a moving vane with turning angle θ = 120. The vane moves away from the nozzle with co
2 answers:
Answer:
The force that must be applied to maintain the vane speed constant is 2771.26 N
Explanation:
Given;
turning angle of the vane = 120°
control volume velocity, u = 10 m/s
absolute velocity, v = 30 m/s
nozzle area = 0.004 m²
The force acting on the vane has horizontal and vertical components:
Based on Reynolds general control volume system;
The horizontal force component of the system, ∑Fₓ = ρW²A(1-cosθ)
where;
ρ is the density of water = 1000 kg/m³
W is the relative velocity = Absolute velocity - control volume velocity
W = v - u
= 30 - 10 = 20m/s
∑Fₓ = ρW²A(1-cosθ) = 1000 x 20² x 0.004 (1 - cos 120) = 2400 N
The vertical force component of the system, ∑Fy = ρW²A(sinθ)
∑Fy = ρW²A(sinθ) = 1000 x 20² x 0.004 x sin(120) = 1385.6 N
The magnitude of the force applied
The force that must be applied to maintain the vane speed constant is 2771.26 N
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Answer:
Part 1: It would be a straight line, current will be directly proportional to the voltage.
Part 2: The current would taper off and will have negligible increase after the voltage reaches a certain value. Graph attached.
Explanation:
For the first part, voltage and current have a linear relationship as dictated by the Ohm's law.
V=I*R
where V is the voltage, I is the current, and R is the resistance. As the Voltage increase, current is bound to increase too, given that the resistance remains constant.
In the second part, resistance is not constant. As an element heats up, it consumes more current because the free sea of electrons inside are moving more rapidly, disrupting the flow of charge. So, as the voltage increase, the current does increase, but so does the resistance. Leaving less room for the current to increase. This rise in temperature is shown in the graph attached, as current tapers.
