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4 years ago

A 25eV electron has a speed of

Physics

2 answers:

dexar [7]4 years ago

5 0

Answer : 3 x 106m/sec

fgiga [73]4 years ago

3 0

Answer: 2.963*10⁶ m/s

Explanation:

Work done = kinetic energy

K.E = eV

½mv² = eV

v² = 2eV / m.

Mass of an electron = 9.11*10-³¹kg

Energy of an electron = 1.60*10-¹⁹J

v² = (2 * 25 * 1.60*10-¹⁹) / 9.11 * 10‐³¹

v = 2.96*10⁶m/s

Note : you'll have to take the square root of velocity (v)

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3 years ago

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.060 m/s and acceleration -0.3

shusha [124]

Answer:

$x_2 = -2.3356$

$v = -1.384 \ m/s$

Explanation:

From the question we are told that

The initial position of the particle is $x_1 = 0.180 \ m$

The initial velocity of the particle is $u = 0.060 \ m/s$

The acceleration is $a = -0.380 \ m/s^2$

The time duration is $t = 3.80 \ s$

Generally from kinematic equation

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=> $v = -1.384 \ m/s$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here s is the distance covered by the particle, so

$(-1.384)^2 = (0.060)^2 + 2(-0.380)* s$

=> $s = -2.5156 \ m$

Generally the final position of the particle is

$x_2 = x_1 + s$

=> $x_2 = 0.180 + (-2.5156)$

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3 years ago

I need help with one through six please

dybincka [34]

Answer:

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2] .000072 = 7.2 × 10⁻⁵

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V = $\frac{50}{10}$

V = 5 m/s

6] Acceleration = $\frac{V1-V2}{time}$

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A = $\frac{15}{3}$

A = 3 m/s²

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