Given that,
Initial Velocity, Vi = 15 m/s
acceleration due to gravity , g = 9.81 m/s²
Time in air, t = ?
Height, h = ?
Speed before striking ground, Vf = ?
Since, we know that,
2as = Vf² - Vi²
2*(-9.81)*s = 0 - 15²
solving above equation we have,
s= 11.46 m
or
h= 11.46 m
Height achieve by arrow will be 11.46 m
Since,
s = Vt
t= s/ V
t = 11.46/ 15
t = 0.76
Total time in air = 2 * t = 2*0.76
Time in air will be 1.53 s
Since,
2as = Vf² - Vi²
2*9.81* 11.46 = Vf² - 0
solving above equation we have,
Vf = 14.99 m/s
or
Velocity of arrow just before striking ground will be 15 m/s approximately.
