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zvonat [6]
3 years ago
5

I’m stuck in B and D. which one is it?

Physics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u>

Option b is correct - Rocky, nearly continuous, found on earth surface.

The reason is <u>i</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>o</u><u>c</u><u>k</u><u>y</u><u> </u><u>s</u><u>u</u><u>r</u><u>f</u><u>a</u><u>c</u><u>e</u><u> </u><u>a</u><u>r</u><u>e</u><u>a</u><u> </u><u>c</u><u>o</u><u>m</u><u>p</u><u>o</u><u>s</u><u>e</u><u>d</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>r</u><u>u</u><u>s</u><u>t</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>u</u><u>p</u><u>p</u><u>e</u><u>r</u><u> </u><u>m</u><u>a</u><u>n</u><u>t</u><u>l</u><u>e</u><u> </u><u>p</u><u>a</u><u>r</u><u>t</u><u>.</u><u> </u><u>B</u><u>a</u><u>s</u><u>i</u><u>c</u><u>a</u><u>l</u><u>l</u><u>y</u><u>,</u><u> </u><u>i</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>o</u><u>u</u><u>t</u><u>e</u><u>r</u><u> </u><u>s</u><u>h</u><u>e</u><u>l</u><u>l</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>r</u><u>t</u><u>h</u><u>.</u>

tatuchka [14]3 years ago
6 0
It is b! the lithosphere is the crust and upper mantle
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A 500 kg sack of coal falls vertically onto a 2000 kg railroad flatcar which was initially moving horizontally at 3 m/s. no exte
Zinaida [17]

Since there are no external forces, including friction, act on the flatcar. after the sack rests on the flatcar, we would assume that momentum is conserved. This means that

total momentum of car before collision = total momentum of car after collision.

Recall,

momentum = mass x velocity

From the information given,

mass of car before collision = 2000

velocity of car before collision = 3

Thus,

total momentum of car before collision = 2000 x 3 = 6000

Also,

mass of sack = 500

mass of car and sack after collision = 500 + 2000 = 2500

velocity after collision = v

momentum after collision = 2500 x v = 2500v

Since momentum is conserved, then

6000 = 2500v

v = 6000/2500

v = 2.4

the speed of the flatcar is 2.4 m/s

6 0
1 year ago
12
Svet_ta [14]

Answer:

See below ~

Explanation:

An object will sink in water when its density is greater than that of water, which is 1 g/cm³.

Volume of the box is <u>1331 cm³</u>. (11³)

Maximum mass of sand will be 1331 g. [because 1331/1331 = 1 g/cm³]

  • Volume of sand = Mass of sand / Density of sand
  • Volume (sand) = 1331/3.5
  • Volume (sand) = 380.29 cm³

If the volume of sand is <u>greater than 380.29 cm³</u>, the box will sink in water.

6 0
3 years ago
What happens to most of the light waves that strike a clear pane of glass? O A. absorption B. diffraction O C. reflection O D. t
Lorico [155]

Answer:reflection

Explanation:

5 0
3 years ago
A square is 1.0 m on a side. Point charges of +4.0 μC are placed in two diagonally opposite corners. In the other two corners ar
finlep [7]

Answer:

<em>B) 1.0 × 10^5 V</em>

Explanation:

<u>Electric Potential Due To Point Charges </u>

The electric potential produced from a point charge Q at a distance r from the charge is

\displaystyle V=k\frac{Q}{r}

The total electric potential for a system of point charges is equal to the sum of their individual potentials. This is a scalar sum, so direction is not relevant.

We must compute the total electric potential in the center of the square. We need to know the distance from all the corners to the center. The diagonal of the square is

d=\sqrt2 a

where a is the length of the side.

The distance from any corner to the center is half the diagonal, thus

\displaystyle r=\frac{d}{2}=\frac{a}{\sqrt{2}}

\displaystyle r=\frac{1}{\sqrt{2}}=0.707\ m

The total potential is  

V_t=V_1+V_2+V_3+V_4

Where V1 and V2 are produced by the +4\mu C charges and V3 and V4 are produced by the two opposite charges of \pm 3\mu\ C. Since all the distances are equal, and the charges producing V3 and V4 are opposite, V3 and V4 cancel each other. We only need to compute V1 or V2, since they are equal, but they won't cancel.

\displaystyle V_1=V_2=k\frac{Q}{r}=9\times 10^9 \frac{4\times 10^{-6}}{0.707}

V_1=V_2=50912\ V

The total potential is

V_t=50912\ V+50912\ V=1\times 10^5\ V

\boxed{V_t=1\times 10^5\ V}

6 0
3 years ago
What is the charge on a hypothetical ion with 35 protons and 37 electrons?
irinina [24]
Charge= Protons- electrons
Charge= 35p-37e= -2

This Ion will have a charge of -2
<span>. </span>
5 0
3 years ago
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