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zvonat [6]
3 years ago
5

I’m stuck in B and D. which one is it?

Physics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

<u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u>

Option b is correct - Rocky, nearly continuous, found on earth surface.

The reason is <u>i</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>r</u><u>o</u><u>c</u><u>k</u><u>y</u><u> </u><u>s</u><u>u</u><u>r</u><u>f</u><u>a</u><u>c</u><u>e</u><u> </u><u>a</u><u>r</u><u>e</u><u>a</u><u> </u><u>c</u><u>o</u><u>m</u><u>p</u><u>o</u><u>s</u><u>e</u><u>d</u><u> </u><u>o</u><u>f</u><u> </u><u>c</u><u>r</u><u>u</u><u>s</u><u>t</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>u</u><u>p</u><u>p</u><u>e</u><u>r</u><u> </u><u>m</u><u>a</u><u>n</u><u>t</u><u>l</u><u>e</u><u> </u><u>p</u><u>a</u><u>r</u><u>t</u><u>.</u><u> </u><u>B</u><u>a</u><u>s</u><u>i</u><u>c</u><u>a</u><u>l</u><u>l</u><u>y</u><u>,</u><u> </u><u>i</u><u>t</u><u> </u><u>i</u><u>s</u><u> </u><u>t</u><u>h</u><u>e</u><u> </u><u>o</u><u>u</u><u>t</u><u>e</u><u>r</u><u> </u><u>s</u><u>h</u><u>e</u><u>l</u><u>l</u><u> </u><u>o</u><u>f</u><u> </u><u>e</u><u>a</u><u>r</u><u>t</u><u>h</u><u>.</u>

tatuchka [14]3 years ago
6 0
It is b! the lithosphere is the crust and upper mantle
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Answer:

I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A

Explanation:

For this case we have the following info given:

Number of Na+ ions 5.7 x10^{11} ions

Each ion have a charge of +e and the crage of the electron is 1.6 x10^{-19}C

The time is given t = 7 ms if we convert this into seconds we got:

t = 7ms * \frac{1s}{1000 ms}= 0.007s

Now we can use the following formula given from the current passing thourhg a meter of nerve axon given by:

Q = Ne

Where N represent the number of ions, e the charge of the electron and Q the total charge

If we replace on this case we have this:

Q= 5.7x10^{11} * (1.6 x10^{-19}C) = 9.12x10^{-8} C

And from the general definition of current we know that:

I =\frac{Q}{t}

And since we know the total charge Q and the time we can replace:

I = \frac{9.12x10^{-8} C}{0.007 s}= 1.30285 x10^{-5} \frac{C}{s}=1.30285 x10^{-5} A = 13.02 \mu A

The current during the inflow charge in the meter axon for this case is 13.02 \mu A

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Inserting the values

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7 0
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Read 2 more answers
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