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3 years ago

1.A little girl kicks a soccer ball. It goes 10 feet and comes back to her. How is this possible?

Physics

2 answers:

marishachu [46]3 years ago

6 0

Something stopped the force and was able to recreate the same amount of force to send it back to her. Example: A pole

Alisiya [41]3 years ago

5 0

I can think of two solutions to this problem...

1) There is a wall in front of the girl ( at a distance of 5 feet from where she is standing). She kicks the ball in the direction of the wall. The ball hits the wall and rebounds back to the girl, thus travelling a distance of 10 feet.

2) She kicks the soccer ball vertically 5 feet high in the air. The ball comes back to her after travelling a total distance of 10 feet ( 5 feet up + 5 feet down).

I found this answer at https://www.quora.com/A-little-girl-kicks-a-soccer-ball-It-goes-10-feet-and-comes-back-to-her-How-is...

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Answer:

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2 years ago

This DNA strand consists of eight pairs of nitrogenous bases. How many different sequences of eight bases can you make?

BaLLatris [955]

Answer:

assuming that there is an equal amount of each base, you can make 65,536 bases

Explanation:

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2 years ago

In 3 meters a person running 0.5 m/s accelerates 1.2 m/s 2. How fast were they going afterward? Choose the right equation for th

Feliz [49]

Answer:

2.72 m/s

Explanation:

In 3 meters a person running 0.5 m/s accelerates 1.2 m/s².

It means,

Distance, s = 3 m

Initial velocity, u = 0.5 m/s

Acceleration, a = 1.2 m/s²

We need to find the final velocity of the person. Using equation of motion to find it as follows :

$v^2-u^2=2as\\\\v^2=2as+u^2\\\\v^2=2\times 1.2\times 3+(0.5)^2\\\\v=2.72\ m/s$

So, the final velocity of the person is 2.72 m/s.

7 0

2 years ago

Oscilloscope amplitude and frequency problem. Study the above graph. The volts/div dial is set to 2 volts/div and the time/div d

denis-greek [22]

Answer:

Amplitude = 8 Volts

Frequency = 0.067 kHz

Explanation:

Note: The missing picture in question is attached for your review.

Given:

Volts/Div = 2 V/div

Time/Div = 5 msec/div

Finding Amplitude:

Now, as you can see in the attached picture, there are 4 division between two peaks of the waveform, so,

$Amplitude = 4 div/volts * 2 volts/ div )\\Amplitude = 8 Volts$

(Multiplying by 2 V/div because oscilloscope dial is set at 2 V/div)

Finding Frequency:

As can be seen in attached picture, 3 division are there for one complete cycle of waveform,so,

$Time Period = 3 div * 5msec /div\\Time Perod = 15 msec$

Since,

$Frequency = \frac{1}{Time Period}\\Frequency = \frac{1}{15m}\\Frequency = 0.067 kHz$

8 0

2 years ago

8. A crate of bananas weighing 3000 N is shipped from South America to New York, where it

LiRa [457]

Answer:

Mechanical advantage = 15

Explanation:

Given the following data;

Output force = 3000N

Input force = 200N

To find the mechanical advantage;

Mechanical advantage = output force/input force

Substituting into the equation, we have

Mechanical advantage = 3000/200

Mechanical advantage = 15

3 0

2 years ago