A ball is dropped from a tall bridge of height 48 m. What will the speed of the ball be immediately before it hits the ground, i
2 answers:
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Answer:
mu=12Tm^2
Explanation:
the magnetic moment mu of a single loop is given by:
where I is the current, B is the magnetic field and A is the area of the loop. By replacing we obtain:
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Answer:
D) the second at the doorknob
Explanation:
The torque exerted by a force is given by:
where
F is the magnitude of the force
d is the distance between the point of application of the force and the centre of rotation
is the angle between the direction of the force and d
In this problem, we have:
- Two forces of equal magnitude F
- Both forces are perpendicular to the door, so
- The first force is exerted at the midpoint of the door, while the 2nd force is applied at the doorknob. This means that d is the larger for the 2nd force
--> therefore, the 2nd force exerts a greater torque