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The Impulse delivered to the baseball is 89 kgm/s.
To solve the problem above, we use the formula of impulse.
⇒ Formula:
- I = m(v-u)................. Equation 1
Where:
- I = Impulse delivered to the baseball
- m = mass of the baseball
- v = Final velocity of the baseball
- u = initial speed of the baseball
From the question,
⇒ Given:
- m = 0.8 kg
- u = 67 m/s
- v = -44 m/s
⇒ Substitute these values into equation 1
- I = 0.8(-44-67)
- I = 0.8(-111)
- I = -88.8
- I ≈ -89 kgm/s
Note: The negative tells that the impulse is in the same direction as the final velocity and therefore can be ignored.
Hence, The Impulse delivered to the baseball is 89 kgm/s.
Learn more about impulse here: brainly.com/question/7973509
Answer:
The velocity with which the jumper strike the mat in the landing area is 6.26 m/s.
Explanation:
It is given that,
A high jumper jumps over a bar that is 2 m above the mat, h = 2 m
We need to find the velocity with which the jumper strike the mat in the landing area. It is a case of conservation of energy. let v is the velocity. it is given by :
g is acceleration due to gravity
v = 6.26 m/s
So, the velocity with which the jumper strike the mat in the landing area is 6.26 m/s. Hence, this is the required solution.
Answer:
μ = 0.309
Explanation:
coefficient of kinetic friction is defined as the ratio of two forces, friction force and the normal force acting on the object.
θ = arctan(15/100)= 8.531⁰
In the vertical direction:
N = mgcosθ = 100 *9.8 *cos(8.531) = 970N
law of conservation of energy implies
mgsinθ - μNx = 1/2m(v₂²-v₁²)
100*9.8*sin (8.531) - μ(970*2) = 1/2(100)(0²-3²)
150.6 - 1940μ = 450
- 1940μ = -600.6
μ = 0.309
We can calculate the work done by the machine by the mathematical formula,
P = W/t
where, P = Power
W = work done
t = time
