A ball is dropped from a tall bridge of height 48 m. What will the speed of the ball be immediately before it hits the ground, i
2 answers:
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Answer:
The time taken by the brick to hit the ground, t = 0.84 s
Explanation:
Given that,
A brick falls from a height, h = 3.42 m
The initial velocity of the brick is zero.
Since the brick is under free-falling. The time equation of a free-falling body when the displacement is given is
t =
where,
h - height from surface in meters
g - acceleration due to gravity
on substituting the values in the above equation,
t =
= 0.84 s
Hence, time taken by the brick to hit the ground is t = 0.84 s
Answer:
t = 0.33h = 1200s
x = 18.33 km
Explanation:
If the origin of coordinates is at the second car, you can write the following equations for both cars:
car 1:
(1)
xo = 10 km
v1 = 55km/h
car 2:
(2)
v2 = 85km/h
For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:
The position in which both cars coincides is: