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balu736 [363]
4 years ago
15

Please helppp.

Physics
1 answer:
cricket20 [7]4 years ago
6 0

The answer is "True".


Please correct me if I'm wrong!! :)

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Explanation:

  • It gives the sensation of vision to our eyes.
  • the speed of sound is 300,000 kilometers per second.
  • It is one of the fundamental constants of nature.
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Which of the following is not a good approximation of the relationship between independent and dependent variables? A. independe
KengaRu [80]

c would be the right answer for this problem

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4 years ago
If a machine exerts a force of 250 N on an object and no work is done, what must have occurred?
valina [46]

Answer:

<h2>1) There is no work done by the machine because</h2><h2>B) The object has not moved</h2><h2>2) There is no work done by the prisoner because</h2><h2>D) The prisoner does no work because the wall goes no distance</h2><h2>3) The kinetic energy when it is half the way down is</h2><h2>6.0 J</h2>

Explanation:

1) As we know that the work done is the product of force and displacement

It is given as

W = Fdcos\theta

so if the object is not displaced due to the force exerted by the object then the work done by the object must be ZERO

so correct answer is

B) The object has not moved

2) As we know that the work done is the product of force and displacement

It is given as

W = Fdcos\theta

As we know that the wall is not displaced due to applied force so here work done by the prisoner must be zero

D) The prisoner does no work because the wall goes no distance

3) As we know by work energy theorem that work done by all forces is equal to change in its kinetic energy

So we will have

W_g + W_f = \frac{1}{2} mv^2

so we will have

3(10)(4) + W_f = \frac{1}{2}(3)(3)^2

120 + W_f = 13.5

W_f = -106.5 J

now when cart moves half the distance then again using the same

W_g + W_f = K

K = 3(10)(2) - \frac{106.5}{2}

K = 6.5 J

8 0
3 years ago
"Caleb misjudges while parking, and bumps his car into a brick wall at 3 MPH. His bumper brings the car to a stop in about 2 inc
8_murik_8 [283]

Explanation:

Using equation of motion to determine the acceleration of the car,

vf^2 = vi^2 + 2 * a * S,

vf = 0

0 = vi^2 + 2 * a * S

Converting mph to m/s,

3 mph * 5280 ft/mi * 12 in/ft * 2.54 cm/in * 1 m/100 cm * 1 h/3600 s

= 3 * 0.445

v = 1.335 m/s

Converting in to m,

2 in * 2.54 cm/in * 1 m/100 cm = 0.0254 m

= 2 * 0.0254

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0 = 1.335^2 + 2 * a * 0.0508

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Mass of car (assumed) = 2000 kg

Force = ma

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4 years ago
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