The equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6) in point slope form is y = x + 8
<h3><u>Solution:</u></h3>
Given that line m contains points (-3, 4) and (1, 0)
We are asked to find the equation of line perpendicular to line containing points (-3, 4) and (1, 0) and passes through (-2, 6)
<em><u>Let us first find slope of the line "m"</u></em>
Given two points are (-3, 4) and (1, 0)
Thus slope of line m is -1
We know that <em>product of slope of given line and perpendicular line are always -1</em>
So, we get
So we have got the slope of perpendicular line is 1 and it passes through (-2, 6)
Let us use the point slope form to find the required equation
<em><u>The point slope form is given as:</u></em>
and m = 1
y - 6 = 1(x - (-2))
y - 6 = x + 2
y = x + 8
Thus equation of required line in point slope form is y = x + 8