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Anna11 [10]
2 years ago
13

Kenneth and 3 friends visited the bowling alley.

Mathematics
1 answer:
yKpoI14uk [10]2 years ago
5 0

Answer:

The shoe rental is a one-time expense for the day.  So that would be 3 * 2.5

The variable is the number of games.  As the question is written, I'm assuming you want the total # of games.  So, the formula for that part would be 5.3x

Putting it together:

(3 * 2.5) + 5.3x = 55.2

Step-by-step explanation:

i asked my pre-algebra teacher and she helped me with the question cuz she wants me to get good grades

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There are two games involving flipping a coin. In the first game you win a prize if you can throw between 45% and 55% heads. In
Nina [5.8K]

Answer:

d) 300 times for the first game and 30 times for the second

Step-by-step explanation:

We start by noting that the coin is fair and the flip of a coin has a probability of 0.5 of getting heads.

As the coin is flipped more than one time and calculated the proportion, we have to use the <em>sampling distribution of the sampling proportions</em>.

The mean and standard deviation of this sampling distribution is:

\mu_p=p\\\\ \sigma_p=\sqrt{\dfrac{p(1-p)}{N}}

We will perform an analyisis for the first game, where we win the game if the proportion is between 45% and 55%.

The probability of getting a proportion within this interval can be calculated as:

P(0.45

referring the z values to the z-score of the standard normal distirbution.

We can calculate this values of z as:

z_H=\dfrac{p_H-\mu_p}{\sigma_p}=\dfrac{(p_H-p)}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_H-p)>0\\\\\\z_L=\dfrac{p_L-\mu_p}{\sigma_p}=\dfrac{p_L-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p_L-p)

If we take into account the z values, we notice that the interval increases with the number of trials, and so does the probability of getting a value within this interval.

With this information, our chances of winning increase with the number of trials. We prefer for this game the option of 300 games.

For the second game, we win if we get a proportion over 80%.

The probability of winning is:

P(p>0.8)=P(z>z^*)

The z value is calculated as before:

z^*=\dfrac{p^*-\mu_p}{\sigma_p}=\dfrac{p^*-p}{\sqrt{\dfrac{p(1-p)}{N}}}=\sqrt{\dfrac{N}{p(1-p)}}*(p^*-p)>0

As (p*-p)=0.8-0.5=0.3>0, the value z* increase with the number of trials (N).

If our chances of winnings depend on P(z>z*), they become lower as z* increases.

Then, we can conclude that our chances of winning decrease with the increase of the number of trials.

We prefer the option of 30 trials for this game.

8 0
2 years ago
Blake wants to break apart the 7 in 5 × 7. Complete the equation to show two different ways Blake could break apart the 7. Choos
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5+2=7, so the first blank is 2. 
For the second blank, you just need two numbers in the box that when added, equals 7. (So 1,6 or 3,4)
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3 years ago
The number 1000 has how many factors of 10
melomori [17]

Answer:

<h2>10³ = 1000</h2>

<h3>∴ 1000 has 3 factors of 10.</h3>

Hope it will be helpful!!!

<h2>My Pleasure!!! </h2>
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This question right here is worth 10 points the first one get it right will earn 10 points;)
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Line l is parallel to line e in the figure below.
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Answer:

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