Find the product.

Mathematics

2 answers:

rusak2 [61]3 years ago

5 0

The product of (3p-7)(3p+7) is a. 9p^2-49

aliina [53]3 years ago

4 0

(3p - 7)(3p + 7) has the form of (a-b)(a+b).
So (a-b)(a+b)= a^2-b^2.
So in (3p - 7)(3p + 7), a=3p and b=7.
So (3p - 7)(3p + 7) = 3p^2 + 7^2 = 9p^2-49.
So (3p-7)(3p+7)= 9p^2 - 49.

You can check your answer (very important):
We'll use p=1.
(3-7)(3+7) = -40
9-49 = -40
The answer has been approved.

Hope this Helps! :)

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Check that 2b+b and 3b have the same value when b is 1,2, and 3. Do 2b+b and 3b have the same value for all values of b? Explain

Inessa [10]

Answer:

Expression 2b+b and 3b have same values for all values of b.

Step-by-step explanation:

Given the two expression $2b+b$ and $3b$ and values of b as 1, 2 and 3.

Consider first expression that is, $2b+b$ .

Substituting the value of $b=1$ ,

$2\left(1\right)+\left(1\right)=2+1=3$ ....1

Substituting the value of $b=2$ ,

$2\left(2\right)+\left(2\right)=4+2=6$ ....2

Substituting the value of $b=3$ ,

$2\left(3\right)+\left(3\right)=6+3=9$ ....3

Consider second expression that is, $3b$ .

Substituting the value of $b=1$ ,

$3\left(1\right)=3$ ....4

Substituting the value of $b=2$ ,

$3\left(2\right)=6$ ....5

Substituting the value of $b=3$ ,

$3\left(3\right)=9$ ....6

For value of b=1, equation 1 and equation 4 are same, for value of b=2, equation 2 and equation 5 are same and for value of b=3 equation 3 and equation 6 are same.

Therefore both expression are same for all values of b.

3 0

2 years ago

Carlos has scored 83, 81, and 73 on his previous three tests. What score does he need on his next test so that his average (mean

disa [49]

Answer:

Step-by-step explanation:

let x be his mark in the fourth test, then

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