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VLD [36.1K]
4 years ago
10

How much 74.3 - 18.26​

Mathematics
2 answers:
USPshnik [31]4 years ago
8 0
56.04 is the correct answe
Oksanka [162]4 years ago
3 0

56.04 is the answer if im correct

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...........answers plz
Ira Lisetskai [31]

Answer:

0

Step-by-step explanation:

m = 21, n = 12

so we just plug these into the equation

(1/3)(21) -1 -(1/2)(12)

(21/3) -1 -(12/2)

7 -1 -6

6 -6

0

3 0
3 years ago
3)<br> Solve the quadratic equation by taking square roots.<br> 3x^2 – 8 = 12
iris [78.8K]

Answer:

The answer is in the photo

Step-by-step explanation:

8 0
4 years ago
&lt;LKJ and &lt;GHI are complementary, find x
Julli [10]

Answer:

This makes exactly 0% percent.

Guess:

GHI>x<LKJ


4 0
4 years ago
help please: A 15 foot long section beam weighs 3,520 pounds. What is the weight of a 3 foot long section of the beam?
yuradex [85]

Answer:

704 pound's

Step-by-step explanation:

What I did was divided 15 by the 3 and then I got 5 which I divided 3520 pound's by 5 which equals 704 pounds. Hope this helps.

5 0
3 years ago
(1-sinx+cosx)^2 = 2(1+sinx)(1+cosx)​
bogdanovich [222]

If you're trying to establish an identity, the given equation is not an identity. The proper identity would be as follows:

(1 - sin(<em>x</em>) + cos(<em>x</em>))² = (1 - sin(<em>x</em>))² + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>) + cos²(<em>x</em>)

… = (1 - 2 sin(<em>x</em>) + sin²(<em>x</em>)) + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>) + cos²(<em>x</em>)

… = 2 - 2 sin(<em>x</em>) + 2 (1 - sin(<em>x</em>)) cos(<em>x</em>)

… = 2 - 2 sin(<em>x</em>) + 2 cos(<em>x</em>) - 2 sin(<em>x</em>) cos(<em>x</em>)

… = 2 (1 - sin(<em>x</em>) + cos(<em>x</em>) - sin(<em>x</em>) cos(<em>x</em>))

… = 2 (1 - sin(<em>x</em>) + cos(<em>x</em>) (1 - sin(<em>x</em>)))

… = 2 (1 - sin(<em>x</em>)) (1 + cos(<em>x</em>))

But if you're trying to solve an equation:

(1 - sin(<em>x</em>) + cos(<em>x</em>))² = 2 (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>))

2 (1 - sin(<em>x</em>)) (1 + cos(<em>x</em>)) = 2 (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>))

(1 - sin(<em>x</em>)) (1 + cos(<em>x</em>)) - (1 + sin(<em>x</em>)) (1 + cos(<em>x</em>)) = 0

(1 + cos(<em>x</em>)) (1 - sin(<em>x</em>) - 1 - sin(<em>x</em>)) = 0

-2 sin(<em>x</em>) (1 + cos(<em>x</em>)) = 0

sin(<em>x</em>) = 0   <u>or</u>   1 + cos(<em>x</em>) = 0

sin(<em>x</em>) = 0   <u>or</u>   cos(<em>x</em>) = -1

[<em>x</em> = arcsin(0) + 2<em>nπ</em>   <u>or</u>   <em>x</em> = arcsin(0) + <em>π</em> + 2<em>nπ</em>]   <u>or</u>

… [<em>x</em> = arccos(-1) + 2<em>nπ</em>]

We have arcsin(0) = 0 and arccos(-1) = <em>π</em>, so the solution set reduces to

<em>x</em> = 2<em>nπ</em>   <u>or</u>   <em>x</em> = (2<em>n</em> + 1)<em>π</em>

(where <em>n</em> is any integer)

7 0
3 years ago
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