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Anastasy [175]
3 years ago
13

Always use significant figure rules. Remember that these rules apply to all numbers that are measurements.

Physics
1 answer:
gogolik [260]3 years ago
6 0
I'll assume \rho=1.8*10^{-6} (resistivity of the wire), I'm pretty sure this is the case given that the units you provided go accordingly with those of resistivity.

For a wire with cross-sectional area A, length l, and resistivity \rho, then its resistance R is given by:
R= \frac{L\rho}{A}

So, for your example:
R= \frac{L\rho}{A}=\frac{(90)(1.8*10^{-6})}{.02}=.0081=8.1*10^{-3}

Hence, the answer is C.
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Plants are producers. What is the role of plants in an ecosystem?
Lilit [14]

Answer:

(C) Plants use oxygen to make their own food

7 0
3 years ago
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How does an atom of strontium 88 become a strontium ion with a+2 charge ?
Oksana_A [137]

<u>Answer:</u>

Strontium atom loses 2 electrons to become an ion.

<u>Explanation:</u>

Strontium (an Alkaline Earth metal) is the 38th element found in the Group 2 of the periodic table.

A Strontium atom has same number of electrons as its protons. It has a +2 electronegativity because it belongs to group 2 of the periodic table so it has the tendency to lose 2 electrons to form a positive ion.

Therefor, Strontium atom loses 2 electrons to become an ion with 2 electrons lesser than its atom.

7 0
3 years ago
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A block with mass M = 3 kg is moving on a flat surface with constant speed v1 = 12 m/s. A bullet with mass m = 0,1 kg is shot at
adelina 88 [10]

The speed does the block move after it is hit by the bullet that remains stuck inside the block will be 23.7 m/sec and it takes 12.07 seconds to stop.

<h3>What is the law of conservation of momentum?</h3>

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

Apply the law of conservation of momentum principle;

m₁v₁+m₂v₂cosΘ =(m₁+m₂)V

3 kg ×  12 m/s +  0,1 kg × 400 m/s cos 20° = (3+0.1)V

36 + 40 cos 20° = 3.1 V

V=23.7 m/sec

The time it takes to stop when the friction coefficient between the block and the surface is 0.2 is found as;

V = u +at

V = 0+ μgt

23..7=0.2× 9.81 ×t

t=12.07 sec

Hence, it takes 12.07 seconds to stop.

To learn more about the law of conservation of momentum refer;

brainly.com/question/1113396

#SPJ1

4 0
3 years ago
Io maintains a constant orbit around Jupiter because
Free_Kalibri [48]

Answer: C . The gravitational pull from Jupiter is much greater than any other forces acting on Io.

Explanation:

Let's begin by the fact Jupiter is a huge massive planet, therefore the bodies that are closest to Jupiter will have a greater gravitational force than the other bodies. That is the situation with Io, the moon closest to Jupiter.

However, Io's orbit is very elliptical and eccentric compared to the outer moons, resulting in the distortion of its shape by the gravitational force.  In fact, Io is considered the most geologically active object in the solar system, due to these variations.

4 0
4 years ago
A uniform, solid cylinder of radius 5.00 cm and mass 3.00 kg starts from rest at the top of an inclined plane that is 2.00 m lon
ch4aika [34]

To solve this problem we will apply the principle of conservation of energy, for which the initial potential and kinetic energy must be equal to the final one. The final kinetic energy will be transformed into rotational and translational energy, so the mathematical expression that approximates this deduction is

KE_i+PE_i = KE_{trans}+KE_{rot} +PE_f

KE_i = 0, since initially cylinder was at rest

PE_f = 0 since at the ground potential energy is zero

The mathematical values are,

mgh = \frac{1}{2} mV^2 + \frac{1}{2}I\omega^2

Here,

m = mass

g= Gravity

h = Height

V = Velocity

I = \frac{mr^2}{2} moment of Inertia in terms of its mass and radius

\omega = \frac{V}{r} Angular velocity in terms of tangential velocity and its radius

Replacing the values we have that

mgh = \frac{1}{2} mv^2 +\frac{1}{2} (\frac{mr^2}{2})(\frac{v}{r})^2

gh = \frac{v^2}{2}+\frac{v^2}{4}

v = \sqrt{\frac{4gh}{3}}

From trigonometry the vertical height of inclined plane is the length of this plane for sin\theta, then

h = 2.00*sin 25

h = 0.845 m

Replacing,

v = \sqrt{\frac{4(9.8)(0.845)}{3}}

V = 3.32 m/s

Therefore the cylinder's speedat the bottom of the ramp is 3.32m/s

6 0
3 years ago
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