Answer:
A) 1.53s
B) 19.8m
C) 2.869m
Explanation:
A) The time of flight for a projectile can be calculated using the formula:
t = 2μsinθ/g
Where; u = velocity
θ = angle
g = acceleration due to gravity (9.8m/s^2)
t = 2 × 15 × sin 30°/9.8
t = 30sin30°/9.8
t = 30 × 0.5/9.8
t = 15/9.8
t = 1.53s
B) The horizontal range (distance) for a projectile can be calculated using the formula:
Range = u²sin2θ/ g
Range = 15² sin 2 × 30 / 9.8
Range = 225 sin 60/9.8
Range = 225 × 0.8660/9.8
Range = 194.855/9.8
Range = 19.8m
C) The maximum height for a projectile can be calculated using the formula:
h = u²sin²θ/2g
h = 15² (sin 30)² / 2 × 9.8
h = 225 × 0.25 / 19.6
h = 56.25/19.6
h = 2.869m
I would say your answer is B, since Newton's 3rd law is, "For every action, there is an equal and opposite reaction."
It's talking about pairs of actions. Sorry if I'm wrong.
Answer:
F = 1.63 x 10⁻⁹ N
Explanation:
Complete question is as follows:
The diagram below shows two bowling balls, A and B, each having a mass of 7.0 kg, placed 2.00 m apart between their centers. Find the magnitude of Gravitational Force?
Answer:
The gravitational force is given by Newton's Gravitational Law as follows:
F = Gm₁m₂/r²
where,
F = Gravitational Force = ?
G = Universal Gravitational Constant = 6.67 x 10⁻¹¹ N.m²/kg²
m₁ = m₂ = mass of each ball = 7 kg
r = distance between balls = 2 m
Therefore,
F = (6.67 x 10⁻¹¹ N.m²/kg²)(7 kg)(7 kg)/(2 m)²
<u>F = 1.63 x 10⁻⁹ N</u>
It seems that you have missed the necessary options for us to answer this question, so I had to look for it. Anyway, here is the answer. You can apply the idea that <span>momentum is constant to solve a problem when the system is not isolated but the time interval when the external forces are exerted is very small. Hope this helps.</span>
Any work a machine does is commanded by a human (in code or any input) or else they are sentient, so humans are still required.
