Answer:

Explanation:
The gravitational potential at a point on the Earth surface is given by:

where
G=6.67×10^-11Nm^2kg^-2 is the gravitational constant
M=5.98×10^24kg is the Earth's mass
R=6.38×10^6 m is the Earth's radius
Substituting the numbers into the equation, we find

Answer:
The strain will come to rest after traveling some distance.
distance traveled = 2500 m
Explanation:
The strain will come to rest after traveling some distance.
Applying,
s = ut+at²/2................... Equation 1
Given: u = initial velocity, a = deceleration, t = time, s = distance
From the question,
Given: u = 50 m/s, t = 100s, a = -0.5 m/s²(deceleration)
Substitute these values into equation 1
s = 50(100)+(-0.5)(100²)/2
s = 5000-2500
s = 2500 m
Hence the distance traveled is 2500 m