Answer:
<em>n = 6 </em>
Step-by-step explanation:
2.3 ×
= (1 × 10³)(2.3 ×
)
(1 × 10³)(2.3 ×
) = (1)(2.3) × (10³)(
) = 2.3 ×
2.3 ×
= 2.3 ×
⇒ 3 + n = 9 ⇒ <em>n = 6</em>
U can use the Pythagorean theorem which is (a^2 + b^2 = c^2) It'll help you a lot
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or greater
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or greater?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.9772
1 - 0.9772 = 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or greater
You are given Kayla's walking distance along the edge of the river 100 ft and marks point C, then she walks 100 ft further and marks point D and she turns 90° and walks until her location, point A, and point C are collinear. She marks point E at this location. ABC and EDC are congruent. thats just what i think it is tho