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Alexxx [7]
2 years ago
15

Which property is illustrated by the following ? if r = -12, then r - 16 = -28​

Mathematics
1 answer:
kondor19780726 [428]2 years ago
4 0
Additive Property of Equality, sometimes called the Addition Property of Equality.

You can add or subtract the same value from both sides of the equation and still maintain the equality.
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You leave home and walk 3 blocks east, then 4 blocks north. How far are you from<br><br>home?
lara31 [8.8K]
I believe the answer would 5 blocks

If you go 3 blocks East and 4 north, they are like the straight sides of a triangle, so to find the diagonal distance, or the shortest distance, you would find the diagonal side of a triangle it is
A squared + B squared = C squared

So 3x3 = 9
And 4x4 = 16
16+9=25
And the square root of 25 is 5

Please correct me if I am wrong and have a good day
4 0
3 years ago
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Andreas93 [3]
13500 m in 250 s
s is the second rate

deomenator is bottom number in a/b, denomenator is b


13500m/250s
use clculator or something to divide or use head
54m/s

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4 0
2 years ago
Suppose that y varies inversely with x.Write an equation for the inverse variation Y=4 when x=7
myrzilka [38]

Answer:

If y varies inversely as x, then we write it as:

y = k/x


where k is some constant.


If we multiply both sides of this equation by x we get an equation for k:

k = x*y


We are given that y=4 when x=7, therefore:

k = 7*4 = 28


Put this back into our original equation to get:

y = 28/x



4 0
2 years ago
In sunlight, a vertical stick has a height of 4 ft and casts a shadow 2 ft long at the same time that a nearby tree casts a shad
marshall27 [118]
Remark
Make up a proportion that relates the tree and its properties to the stick and its properties.

Givens
Stick height (s_h) = 4
Stick shadow(s_s) = 2
Tree shadow = t_s = 18
Tree height = x

Formula
s_h / s_s = x / t_s

Substitute and solve.
4/2 = x / 18  Cross multiply
4*18 = 2 * x
72 = 2x        Divide by 2
72/2 = x       
x = 36

The height of the tree is 36 feet.     
6 0
3 years ago
25 Points ! Write a paragraph proof.<br> Given: ∠T and ∠V are right angles.<br> Prove: ∆TUW ∆VWU
vladimir2022 [97]

Answer:

Δ TUW ≅ ΔVWU ⇒ by AAS case

Step-by-step explanation:

* Lets revise the cases of congruent for triangles

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ  

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ  

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles

 and one side in the 2ndΔ

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets solve the problem

- There are two triangles TUW and VWU

- ∠T and ∠V are right angles

- LINE TW is parallel to line VU

∵ TW // VU and UW is a transversal

∴ m∠VUW = m∠TWU ⇒ alternate angles (Z shape)

- Now we have in the two triangles two pairs of angle equal each

 other and one common side, so we can use the case AAS

- In Δ TUW and ΔVWU

∵ m∠T = m∠V ⇒ given (right angles)

∵ m∠TWU = m∠VUW ⇒ proved

∵ UW = WU ⇒ (common side in the 2 Δ)

∴ Δ TUW ≅ ΔVWU ⇒ by AAS case

7 0
2 years ago
Read 2 more answers
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