Question

How many moles of magnesium oxide are produced by the reaction of 0.315 moles of magnesium nitride with 0.295 moles of water?

Answer 1

Answer:

0.1475 moles

Explanation:

From the balanced equation of reaction:

$Mg_3N_2(s)+6H_2O_{(l)}--->2NH_3_{(aq)}+3Mg(OH)_2_{(aq)}$

1 mole of magnesium nitride reacts with 6 moles of water to produce 3 moles of magnesium hydroxide.

One of the reactants will be limited.

1 mole of magnesium nitride requires 6 moles of water.

0.315 moles magnesium nitride will require: 0.315 x 6 = 1.89 moles water

But there is only 0.295 moles of water, hence, water will be limited.

From the reaction:

6 moles of water produces 3 moles of magnesium hydroxide.

Hence, 0.295 moles of water will produce;

                            0.295 x 3/6 = 0.1475 moles of magnesium hydroxide

Magnesium hydroxide will decompose according to the following equation:

$Mg(OH)_2 ---> MgO + H_2O$

1 mole of magnesium hydroxide will produce 1 mole of Magnesium oxide.

0.1475 moles of magnesium hydroxide will produce 0.1475 moles of magnesium oxide.

Hence, 0.1475 moles of magnesium oxide will be produced by the reaction of 0.315 moles of magnesium nitride with 0.295 moles of water