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sleet_krkn [62]
3 years ago
10

C3H8(g) + 5O2(g) ⟶ 3CO2(g) + 4H2O(g) H = -2220 kJ If 865.9 g of H2O is produced during this combustion, how much heat is generat

ed? Do not include the negative sign in your answer. Express the answer to the nearest whole number, or round to the nearest ones place. The molar mass of H2O is 18.02 g/mol.
Chemistry
1 answer:
dem82 [27]3 years ago
5 0

Answer:

3 × 10⁴ kJ

Explanation:

Step 1: Write the balanced thermochemical equation

C₃H₈(g) + 5 O₂(g) ⟶ 3 CO₂(g) + 4 H₂O(g) ΔH = -2220 kJ

Step 2: Calculate the moles corresponding to 865.9 g of H₂O

The molar mass of H₂O is 18.02 g/mol.

865.9 g × 1 mol/18.02 g = 48.05 mol

Step 3: Calculate the heat produced when 48.05 moles of H₂O are produced

According to the thermochemical equation, 2220 kJ of heat are evolved when 4 moles of H₂O are produced.

48.05 mol × 2220 kJ/4 mol = 2.667 × 10⁴ kJ ≈ 3 × 10⁴ kJ

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Llana [10]

Answer:

239.7 g

Explanation:

Step 1: Write the balanced equation

2 LiBr + I₂ → 2 LiI + Br₂

Step 2: Convert the molecules of iodine to moles

We have 9.033 × 10²³ particles (molecules) of iodine. In order to convert molecules to moles, we will use the <em>Avogadro's number</em>: there are 6.022 × 10²³ molecules of iodine in 1 mole of iodine.

9.033 \times 10^{23}molecule \times \frac{1mol}{6.022 \times 10^{23}molecule} =1.500mol

Step 3: Calculate the moles of bromine produced

The <em>molar ratio of I₂ to Br₂</em> is 1:1. Then, the moles of bromine produced are 1.500 moles.

Step 4: Calculate the mass of bromine

The <em>molar mass of bromine</em> is 159.81 g/mol. The mass corresponding to 1.500 moles is:

1.500mol \times \frac{159.81g}{mol} = 239.7 g

7 0
4 years ago
Read the following chemical equations. Reaction 1: H2S + Cl2 → 2HCl + S Reaction 2: Fe + S → FeS Which of the following statemen
DIA [1.3K]

Answer:

D. Chlorine is reduced in reaction 1 and iron is oxidized in reaction 2.

Explanation:

  • Reduction is the process where by the Oxidation number or state of an element or substance is reduce.
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black hole

hope it helps

edit: neutron star

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