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What is the significance sodium hydroxide and hydrochloric acid

hammer [34]

Answer:

They are a base and an acid, so they neutralize each other.

Explanation:

Sodium hydroxide is a strong base. Hydrochloric acid is a strong acid.

They react with (neutralize) each other to form a salt (sodium chloride) and water.

NaOH + HCl ⟶ NaCl + H₂O

5 0

2 years ago

Explain how you would test the presence of oxygen and hydrogen gases.

Vedmedyk [2.9K]

Place a burning splint near the opening of a test tube. If a popping noise occurs, it's probably hydrogen. Place a glowing splint in the test tube, and if it reignites, it could be oxygen. Place a burning splint into a test tube, and if it goes out, it could be carbon dioxide.

5 0

2 years ago

Wat are representative elements

AnnyKZ [126]

In chemistry and atomic physics, the main group is the group of elements whose lightest members are represented by helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, and fluorine as arranged in the periodic table of the elements

7 0

2 years ago

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The electrolysis of water forms H2 and O2. 2H2O Right arrow. 2H2 O2 What is the percent yield of O2 if 10.2 g of O2 is produced

Mama L [17]

Answer:

67.5%

Explanation:

Step 1: Write the balanced equation for the electrolysis of water

2 H₂O ⇒ 2 H₂ + O₂

Step 2: Calculate the theoretical yield of O₂ from 17.0 g of H₂O

According to the balanced equation, the mass ratio of H₂O to O₂ is 36.04:32.00.

17.0 g H₂O × 32.00 g O₂/36.04 g H₂O = 15.1 g O₂

Step 3: Calculate the percent yield of O₂

Given the experimental yield of O₂ is 10.2 g, we can calculate its percent yield using the following expression.

%yield = (exp yield / theoret yield) × 100%

%yield = (10.2 g / 15.1 g) × 100% = 67.5%

8 0

2 years ago

This diagram shows the forces acting on a car. The center dot represents the car, and the arrows represent the forces acting on

Mariulka [41]

Answer : The correct option is B- Towards the left.

Solution : Given,

Force on car in upward direction, $F_1$ = 6000 N

Force on car in downward direction, $F_2$ = 6000 N

Force on car in right direction, $F_3$ = 5000 N

Force on car in left direction, $F_4$ = 6000 N

Force : Force is equal to the mass multiplied by the acceleration. The force is directly proportional to the acceleration.

Formula : F = m × a

where, F is force, m is mass and a is acceleration.

From the given diagram we conclude that the $F_1$ and $F_2$ are in opposite direction and the force acting on car are same. So, their net force is zero.

And in case of $F_3$ and $F_4$ , the net force will not be zero because force acting on car are different. The car will accelerate towards left direction because $F_4$ is higher than the $F_3$ .

So, the car will accelerate towards left direction.

3 0

2 years ago

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