It would be: 124/100 = 62/50 = 31/25
So, your final answer is 31/25
Hope this helps!
Answer:
25%
Step-by-step explanation:
First we calculate the probability of rolling a number greater than 3, that is, it can be 4, 5 or 6.
The probability of each number is 1/6, so:
P1 = (1/6) + (1/6) + (1/6) = 3/6 = 1/2
Then, we calculate the probability of rolling a prime number, that is, 2, 3 or 5.
As we have again 3 numbers, the probability P2 will also be 1/2
Then, the final probability is the product of both P1 and P2:
P = P1 * P2 = (1/2) * (1/2) = 1/4 = 25%
The numbers given in the problem above are part of an arithmetic sequence with first and sixth terms equal to -21 and -36, respectively. Firstly, calculate for the common difference (d).
d = (-36 - -21) / (6 - 1) = -3
The arithmetic mean is calculated by adding -3 to the term prior to it.
a2 = -21 + -3 = -24 a3 = -24 + -3 = -27
a4 = -27 + -3 = -30 a5 = -30 + -3 = -33
Thus the four arithmetic means are -24, -27, -30, and -33.
Answer:
22.22% probability the game will be in December
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question:
14+13+12+15 = 54 games.
Of those, 12 are in December.
So
12/54 = 0.2222
22.22% probability the game will be in December
$-1,154. All you have to do is subtract 600 from -554.