All categories

3 years ago

The cost of 24 bottles of water is $6. Which expression shows how to find the cost of 10 bottles of water?

1 answer:

4 0

So first you need to find out how much one water bottle cost.
6/24= 0.25
Okay now you need to find how much it would cost for 10.
so you would times 10 by $0.25:
10*0.25= $2.50
So $2.50 would be you answer.
Hope that helps!!
Have a wonderful day!!

You might be interested in

A tank fills in 8 hours but evaporates in 12. how long will it take to fill the tank

Neko [114]

1 = h · $\frac{1}{8}$ - h · $\frac{1}{12}$

Solve for h.
(units in hours)

7 0

3 years ago

HELPPPP! Which expression is equivalent to 7Vx^2/5Vy^2

baherus [9]

Pretty sure it’s the first answer

4 0

2 years ago

Read 2 more answers

Suppose that a college determines the following distribution for X = number of courses taken by a full-time student this semeste

lidiya [134]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$ In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$ And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

Step-by-step explanation:

Previous concepts

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

Solution to the problem

For this case we have the following distribution given:

X 3 4 5 6

P(X) 0.07 0.4 0.25 0.28

We can calculate the mean with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 3*0.07 +4*0.4 +5*0.25 +6*0.28= 4.74$

In order to find the variance we need to calculate first the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 3^2*0.07 +4^2*0.4 +5^2*0.25 +6^2*0.28= 23.36$

And the variance is given by:

$Var(X) = E(X^2) +[E(X)]^2 = 23.36 -[4.74]^2 = 0.8924$

And the deviation would be:

$Sd(X) =\sqrt{0.8924} =0.9447$

3 0

3 years ago

6. The population of a town is 680 000 correct to the nearest 10 000. Write down

serg [7]

Answer:

a) 675 000

b) 685 000

Step-by-step explanation:

The population of a town is 680 000 correct to the nearest 10 000.

a) To find it lower bound, we level of accuracy by 2 and then subtract from 680 000

The lower bound is:

680 000-5000=675,000

Therefore the least possible population of the town is 675 000

b) We repeat the same process to find the upper bound

680 000+5000=685,000

6 0

3 years ago

What is m in 1/3m = -4

ahrayia [7]

Answer:

m=-12

Step-by-step explanation:

Let's solve your equation step-by-step.

1 / 3 m= −4

Step 1: Multiply both sides by 3.

3*( 1 / 3 m) = (3) * (−4)

m=−12

3 0

3 years ago