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docker41 [41]
3 years ago
11

How does the mitochondria help to maintain homeostasis for the cell?

Physics
1 answer:
Sergeu [11.5K]3 years ago
6 0
It extracts energy from food for the cell.
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Karl measures the current through a resistor. What else will he need to measure in order to work out its resistance?
Shkiper50 [21]

Answer:

The voltage (V)

Explanation:

Ohms, in his law, has explained the relationship between current, resistance and voltage.

Ohm's law, which states that the voltage passing through a resistor is directly proportional to both the current and the resistance of the resistor, has the following equation:

V = IR

Where;

V = voltage (volts)

I = current (Amperes)

R = resistance (ohms)

According to this question, Karl measures the current, I, through a resistor. In order to calculate his resistance, R, he will need to measure the voltage, V.

7 0
3 years ago
What voltage can be applied by a resistor<br><br>190 Ω and 100 A?
Anettt [7]

Answer:

V=IR

V=100×190

=19000 V

4 0
3 years ago
Hi, anyone has any ideas for making your own planet? Be creative : )
xenn [34]

Answer:

I would make all the people depressed but that would be normal and all the happy people were considerd sped.

Explanation:

6 0
3 years ago
Read 2 more answers
A football is kicked into the air from an initial height of 4 feet. The height, in feet, of the football above the ground is giv
kakasveta [241]

Answer: 0.5 seconds or 2.625 seconds

Explanation:

At t = 0, The ball is 4 ft above the ground.

The height of the football varies with time in the following way:

s(t) = -16 t² + 50 t + 4

we need to find the time in which the height would of the football would be 25 ft:

⇒25 = -16 t² + 50 t + 4

we need to solve the quadratic equation:

⇒ 16 t² - 50 t + 21 = 0

t = \frac{50 \pm \sqrt{50^2-4\times 16\times 21}}{2\times16}

⇒ t = 0.5 s or 2.625 s

Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.

3 0
3 years ago
Read 2 more answers
If we increase the driving frequency in a circuit with purely resistive load, how do the amplitudes VR and IR change?
Lady_Fox [76]

Answer:

V = I R    

expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

Explanation:

In a purely resistive circuit, the Ohm relation, m for which

          V = I R

We see that the previous expression does not depend on the frequency, so when changing this quantity does not change the voltage or the current in the circuit.

This does not happen in circuits with capacitors or inductors where there is an explicit dependence on frequency.

3 0
3 years ago
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