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Anastasy [175]
2 years ago
9

Releases hydrogen ions in water is that acid or bases?

Physics
1 answer:
wolverine [178]2 years ago
6 0
Acid it is i believe........
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Besides providing food and lumber, some trees are valuable natural resources because they contain substances that help make ____
kondaur [170]
Medicines would be your answer


6 0
3 years ago
Read 2 more answers
Twin A makes a one way trip at 0.6c to a star 12 light years away while twin B stays on Earth. Each twin sends the other a signa
hram777 [196]

Answer:

8 signals received by twin A during the trip.

Explanation:

Given that,

Distance = 12 light year

Speed = 0.6 c

Time = 1 year

We need to calculate the time by A

Using formula of time

T=t\sqrt{\dfrac{1+\dfrac{v}{c}}{1-\dfrac{v}{c}}}

Put the value into the formula

T=1\sqrt{\dfrac{1+0.6}{1-0.6}}

T=2\ years

Similarly,

The expression for distance cover by A

D=d\sqrt{1-\dfrac{v^2}{c^2}}

D=12\sqrt{1-(0.6)^2}

D=9.6\ ly

We need to calculate the time

Using formula of time

t=\dfrac{D}{v}

t=\dfrac{9.6}{0.6}

t=16\ years

We need to calculate the signals received by twin A

Using formula for number of signals

n=\dfrac{t}{T}

Put the value into the formula

n=\dfrac{16}{2}

n=8\ signals

Hence, 8 signals received by twin A during the trip.

7 0
3 years ago
Velocity is:
sleet_krkn [62]

Answer:

d

Explanation:

Solution:-

- The Quantity of theory of money states:

                      M * V = P * Y

Where,

           M = Money supply

           V = Velocity of money exchange

           P = The price level

           Y = Real GDP

- By re-arranging the formula and solving for "V" we have:

                     V = P*Y / M

- The expression on right hand side increases if exchange of dollars increases.

3 0
3 years ago
Object A of mass 0.70 kg travels horizontally on a frictionless surface at 20 m/s. It collides with object B, which is initially
AnnZ [28]

Answer:

25.71 kgm/s

Explanation:

Let K₁ and K₂ be the initial and final kinetic energies of object A and v₁ and v₂ its initial and final speeds.

Given that K₂ = 0.7K₁

1/2mv₂² = 0.7(1/2mv₁²)

v₂ = √0.7v₁ = √0.7 × 20 m/s = ±16.73 m/s

Since A rebounds, its velocity = -16.73 m/s and its momentum change, p₂ = mΔv = m(v₂ - v₁) = 0.7 kg (-16.73 - 20) m/s = 0.7( -36.73) = -25.71 kgm/s.

Th magnitude of object A's momentum change is thus 25.71 kgm/s

6 0
3 years ago
When a 2.50 kg object is hung vertically on a certain light spring described by hookes law the spring stretches 2.76 cm.
Readme [11.4K]
F=K*X,
F=M*a 

M*a=K*X

2.5*9.81=K*0.0276

24.525=K*0.0276

24.525/0.0276=K

K= 888.6 N/m ---- force constant 

assuming 2.5 refers to the new extension, just divide F/ 0.025
to get

981N/m 


8 0
3 years ago
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