Answer:
The final temperature of the entire water sample after all the ice is melted, is 12,9°C. We should realize that if there is no loss of heat in our system, the sum of lost or gained heat is 0. It is logical to say that the temperature has decreased because the ice gave the water "heat" and cooled it
Thats all i know
The thermal energy will flow from the hotter object to the cooler object until their temperatures are equal i.e. until they reach equilibrium.
Answer:
D. equilibrium
Answer:
- HNO3(aq)+NH3(aq)→NH4NO3(aq)+H2O(l): neutralization.
- 2Cu(s)+O2(g)→2CuO(s): redox.
- NaCl(aq)+AgNO3(aq)→NaNO3(aq)+AgCl(s): precipitation.
- 2LiOH(aq)+H2SO4(aq)→Li2SO4(aq)+2H2O(l): neutralization.
- CaCl2(aq)+K2CO3(aq)→2KCl(aq)+CaCO3(s): precipitation.
Explanation:
Hello,
Based on the given reaction and their classification as redox, neutralization or precipitation, one obtains:
- HNO3(aq)+NH3(aq)→NH4NO3(aq)+H2O(l): neutralization as ammonia which is a base, is reacting with nitric acid which is an acid to yield ammonium nitrate which is a base.
- 2Cu(s)+O2(g)→2CuO(s): redox as both copper's and oxygen's oxydation states change by increasing by 2 and reducing by 2 respectively.
- NaCl(aq)+AgNO3(aq)→NaNO3(aq)+AgCl(s): precipitation as the inital reactants are soluble but the yielded silver chloride is not.
- 2LiOH(aq)+H2SO4(aq)→Li2SO4(aq)+2H2O(l): neutralization as lithium hydroxide which is a base reacts with sulfuric acid which is an acid to yield lithium sulfate which is a salt.
- CaCl2(aq)+K2CO3(aq)→2KCl(aq)+CaCO3(s): precipitation since both calcium chloride and potassium carbonate are soluble whereas calcium carbonate is not.
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Answer:
A. 0.01 M
Explanation:
Molar mass (KCl) = 39.1 + 35.5 = 74.6 g/mol
0.37 g KCl * 1 mol/74.6 g = 0.004960 mol
500 mL = 0.5 L
Molarity = mol solute/L solution = 0.004960 mol/0.5 L = 0.01 M
Zero on a pH scale is very A. acidic, and 14 on a pH scale is very basic.
The lower the number on the scale, the more acidic it is.
