Bond formation is the way in which atoms interact to form compounds.
<h3>What is bond formation?</h3>
Bond formation is the way in which atoms interact to form compounds. The following are the kind of bonds formed by the atoms;
C and AI - ionic bond
N and P - covalent bond
N and O - covalent bond
The bonds in each of the lattices are;
CuO - ionic bond
Hg - metallic bond
P2O5 - covalent bond
P - covalent bond
CaCl2 - ionic bond
The following is a depiction of the processes shown;
Na0 →Na+1 - oxidation
P0→P+5 - oxidation
AI+3 → AI0 - reduction
The balanced reaction equations are;
2H2O + F2 → 2HF + O2
SO2 + 3H2 → H2S + 2H2O
2H2SO4 + C → 2SO2+CO2+2H2O
Learn more about balancing reaction equation:brainly.com/question/22064431
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Given the values above, in order to know the molar concentration or the molarity of a solution containing 171 g of sucrose in 1.25L solution, here is the solution that you should follow: So,
MM = 342 (g/mol)
171 (g) / 342(g/mol) = x mol of sucrose
<span>x moles of sucrose/ 1.25 L = Molarity of solution
</span>Hope this is the answer that you are looking for.
Answer:
Ions and ionic bonds. Some atoms become more stable by gaining or losing an entire electron (or several electrons). When they do so, atoms form ions, or charged particles. Electron gain or loss can give an atom a filled outermost electron shell and make it energetically more
Answer:
These two are equivalent and valid:
Explanation:
The molecular superscripts for each atom in the <em>molecular formula</em> are determined by the number of times that the mass of the<em> empirical formula</em> is contained in the<em> molar mass</em>.
<u />
<u>1. Determine the mass of the empirical formula:</u>
:
Atomic masses:
- O: 15.999g/mol
- C: 12.011g/mol
- N: 14.007g/mol
- Cl: 35.453g/mol
Total mass:
- 15.999g/mol + 12.011g/mol + 14.007g/mol + 35.453g/mol = 77.470g/mol
<u />
<u>2. Divide the molar mass by the mass of the empirical formula:</u>
- 232.41g/mol / 77.470g/mol = 3
<u>3. Multiply each superscript of the empirical formula by the previous quotient: 3</u>
Or:
You might also write CN as a group: