Answer:
A
Step-by-step explanation:
We know that identity:
cos^2x+sin^2x=1.
From that we have:
cos^2x=1-sin^2x.
So it is:
cos^2x-sin^x=(1-sin^2x)-sin^2x=1-2sin^2x.
And this is A).
B) is not treu because cos^2 is not sin^2x+1
C) is not true because cos^2x-sin^x=1 is false.
D) is not treu because cos^2x is not sin^2x-1
Answer:
in triangle PQR, <P - <Q = 20 degrees, <Q - <R = 50 degrees, find <P, <Q, <R
Q = 30, R = 80, P = 50
Step-by-step explanation:
in triangle PQR, <P - <Q = 20 degrees, <Q - <R = 50 degrees, find <P, <Q, <R
R = Q
+50, 80=30+50
P = Q
+
20, 50=30+20
Q = 30, R = 80, P = 50
Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then

Using this rule, we get



Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).