Question

1.- Que distancia recorrió una carga de 2,5x10-6 coul, generando así un campo eléctrico de 55new/coul.​

Answer 1

Answer:

r = 20.22 m

Explanation:

Given that,

Charge,$q=2.5\times 10^{-6}\ C$

Electric field, $E=55\ N/C$

We need to find the distance. We know that, the electric field a distance r is as follows :

$E=\dfrac{kq}{r^2}\\\\r=\sqrt{\dfrac{kq}{E}}\\\\r=\sqrt{\dfrac{9\times 10^9\times 2.5\times 10^{-6}}{55}}\\\\r=20.22\ m$

So, the required distance is 20.22 m.