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dimaraw [331]
3 years ago
5

1.- Que distancia recorrió una carga de 2,5x10-6 coul, generando así un campo eléctrico de 55new/coul.​

Physics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

r = 20.22 m

Explanation:

Given that,

Charge,q=2.5\times 10^{-6}\ C

Electric field, E=55\ N/C

We need to find the distance. We know that, the electric field a distance r is as follows :

E=\dfrac{kq}{r^2}\\\\r=\sqrt{\dfrac{kq}{E}}\\\\r=\sqrt{\dfrac{9\times 10^9\times 2.5\times 10^{-6}}{55}}\\\\r=20.22\ m

So, the required distance is 20.22 m.

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What are used by organisms for long-term energy storage
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Answer:

Fatty acids.

Explanation:

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-Fatty acids are more calori dense hence them being ideal for long term energy storage.

4 0
3 years ago
How deep can an object with 6360N hitting on a sponge get ???
borishaifa [10]

Answer:

The sponge must go \dfrac{636}{m}\ \text{meter} deep

Explanation:

If F = 6360 N, then it is required to find how deep can an object with this force hitting on a sponge get.

We know that, F = mgh

m is mass

g is acceleration due to gravity

h=\dfrac{F}{mg}\\\\h=\dfrac{6360}{10m}\\\\h=\dfrac{636}{m}\ \text{meter}

So, the sponge must go \dfrac{636}{m}\ \text{meter} deep.

5 0
3 years ago
An FM radio station transmits a signal with a frequency of 89.1 MHz. Give the wavelength in meters. (use at least three signific
STALIN [3.7K]

Answer:

3m

Explanation:

89.1 MHz means

89.1×10^6 cycles/second.

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3.0×10^8meters/second

Wavelength = Speed/Frequency

The wavelength of a

89.1MHz radio signal is

3.0×10^8/89.1x10^6

= 0.03x10^2

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7 0
3 years ago
A baby elephant trots in a straight line along a river. The horizontal position of the elephant in meters over
mote1985 [20]

Answer:

Displacement -6

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Explanation:

5 0
3 years ago
Which one is correct and why?​
Gelneren [198K]

'A' and 'C' are exactly the same circuit, except the voltmeter's terminals are flipped.

'A' is the correct way to hook everything up.

If you start at the positive terminal of the battery, and follow the flow of current through the circuit and around to the negative terminal, you're following the path where the voltage gets lower and lower and lower all the way.

So each time you come to any device in the circuit ... whether it's a resistor or a meter ... you would be hitting the positive side of it first, and then the voltage where you come out on the other side of it would be lower.  

So the left side of the resistor is more positive, and the right side is more negative.  The voltmeter is connected correctly in 'A', but it's backwards in 'C'.  If you connect the voltmeter like in 'C' and turn things on, the voltmeter will try  to go <em>down</em> from zero.  You can't read the number on it, and It's possible that the voltmeter might be damaged.  

6 0
3 years ago
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