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dimaraw [331]
3 years ago
5

1.- Que distancia recorrió una carga de 2,5x10-6 coul, generando así un campo eléctrico de 55new/coul.​

Physics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

r = 20.22 m

Explanation:

Given that,

Charge,q=2.5\times 10^{-6}\ C

Electric field, E=55\ N/C

We need to find the distance. We know that, the electric field a distance r is as follows :

E=\dfrac{kq}{r^2}\\\\r=\sqrt{\dfrac{kq}{E}}\\\\r=\sqrt{\dfrac{9\times 10^9\times 2.5\times 10^{-6}}{55}}\\\\r=20.22\ m

So, the required distance is 20.22 m.

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Answer: The current must be equal to \frac{\sqrt{33} }{6} amps, or ~0.9574 amps.

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I = \sqrt{\frac{P}{R} }

Where P represents power in watts, R represents resistance in ohms, and I represents current in amperes.

You can then substitute 60 and 55 into the equation to find I:

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