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dimaraw [331]
3 years ago
5

1.- Que distancia recorrió una carga de 2,5x10-6 coul, generando así un campo eléctrico de 55new/coul.​

Physics
1 answer:
sergiy2304 [10]3 years ago
3 0

Answer:

r = 20.22 m

Explanation:

Given that,

Charge,q=2.5\times 10^{-6}\ C

Electric field, E=55\ N/C

We need to find the distance. We know that, the electric field a distance r is as follows :

E=\dfrac{kq}{r^2}\\\\r=\sqrt{\dfrac{kq}{E}}\\\\r=\sqrt{\dfrac{9\times 10^9\times 2.5\times 10^{-6}}{55}}\\\\r=20.22\ m

So, the required distance is 20.22 m.

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Mass will remain constant on both planet, let mass of the object be "m".
let x be the <span>acceleration due to gravity on the surface of mars.
Weight of object on earth = m *g , where g is </span><span>acceleration due to gravity on the surface of earth
</span>⇒350 =  m *  9.8
⇒m = 350  /  9.8                        .............................equation(1)
Weight of object on mars = m * x , where x is acceleration due to gravity on the surface of mars
134  =   m   *  x                           .............................equation(2)
putting the value of m from equation (1) in equation(2) , we get,
x     =   (134  *  9.8) / 350
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