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2 years ago

The net force on an object moving with constant speed in circular motion is in which direction

Physics

1 answer:

ipn [44]2 years ago

7 0

Answer:

the net force is the same direction as the acceleration

Explanation:

so toward the center of the circle about which the object is constantly moving.

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What causes earthquakes,tsunami, and volcanic eruptions to happen certain places and not others

Dafna11 [192]

These are all caused by tectonic plate movements. Some areas of the globe are more susceptible to these disasters because they are on or near a fault line where the Earth’s tectonic plates rub against one another, slip beside and under each other, or collide. The places near fault lines are more likely to see earthquakes, tsunamis, and volcanic activity.

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3 years ago

8. What is the rate of change in an object’s position?

adelina 88 [10]

A similar but separate notion is that of velocity, which the rate of change of position. Example . If p(t) is the position of an object moving on a number line at time t (measured in minutes, say), then the average rate of change of p(t) is the average velocity of the object, measured in units per minute.

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3 years ago

Read 2 more answers

[Assume g = 10m/s?] If a girl is running along a straight road with a uniform velocity 1.5 m/s, find her acceleration. (Ans: 0)

DerKrebs [107]

Answer:

Her acceleration is 0 m/s²

Explanation:

We note that the motion of the girl is on a straight road, therefore;

The vertical acceleration (e.g. due to gravity, g) on the horizontal motion = 0

The horizontal acceleration, a = (Change in velocity, Δv)/(Change in time, Δt)

For uniform velocity, the change in velocity, Δv = 0

Therefore, fore any change in time, Δt, we have;

a = Δv/Δt

Her acceleration, a = 0/Δt = 0

Her acceleration, a = 0 m/s²

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2 years ago

You make tea with 0.50 kg of 85.0Â°C water and let it cool to room temperature 120.0Â°C2.

dedylja [7]

Answer:

Explanation:

a ) Entropy change dS = dQ/T

= mcdT /T

Integrating both sides

S₂ - S₁ = - mclnT₂ /T₁

= - .5 X 4200 ln (85+273) /( 20 + 273 )

.5 X 4200 ln 358/ 293

= - 417.6 J/K

Entropy change will be negative as heat is lost by the system .

b ) Sine there is no change in the temperature of air , This heat will enter air at temperature ( 20+ 273) K = 293 K

Heat entering air

= .5 x 4200 x 65

= 136500 J

Change in entropy

136500 / 293 ( room temperature is constant at 293k

= + 465.87 J/K

Entropy change will be positive as heat is gained by the system .

Total change in the entropy of the system (tea + air )

= +465.87 - 417.6

= 48.27 J/K

Entropy change will be negative as heat is lost by the system .

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3 years ago

In a game of pool, a cue ball rolls without slipping toward the stationary eight ball with a momentum of 0.23 kg m/s. After the

ella [17]

Answer: 0.22

Explanation: Subtract 0.01kg from 0.23kg

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2 years ago